Answer:
The answer is
<h2>28 kg</h2>
Explanation:
The mass of an object given it's momentum and velocity / speed can be found by using the formula

where
m is the mass
p is the momentum
v is the speed or velocity
From the question
p = 280 kg/ms
v = 10 m/s
The mass of the object is

We have the final answer as
<h3>28 kg</h3>
Hope this helps you
because water is loosely packed but when it is cold it becomes closely packed in order to form ice and thus the force attraction between them also increase.
Answer:
15 cm
Explanation:
Dari pertanyaan yang diberikan di atas, diperoleh data sebagai berikut:
Gaya 1 (F₁) = 225 N
Jarak terpisah 1 (d) = 5 cm
Gaya 2 (F₂) = 25 N
Jarak terpisah 2 (d₂) =?
Kita dapat memperoleh persamaan yang berkaitan dengan gaya dan jarak muatan dua titik dengan menggunakan rumus berikut:
F = Kq₁q₂ / d²
Perbanyak silang
Fd² = Kq₁q₂
Menjaga Kq₁q₂ konstan, kita memiliki:
F₁d₁² = F₂d₂²
Dengan rumus di atas maka diperoleh jarak sebagai berikut:
Gaya 1 (F₁) = 225 N
Jarak terpisah 1 (d) = 5 cm
Gaya 2 (F₂) = 25 N
Jarak terpisah 2 (d₂) =?
F₁d₁² = F₂d₂²
225 × 5² = 25 × d₂²
225 × 25 = 25 × d₂²
5625 = 25 × d₂²
Bagilah kedua sisinya dengan 25
d₂² = 5625/25
d₂² = 225
Hitung akar kuadrat dari kedua sisi
d₂ = √225
d₂ = 15 cm
Oleh karena itu, muatan dua titik harus berjarak 15 cm untuk memiliki gaya tarik 25 N
Answer:
The speed of the object just before it hits Earth is 
(A) is correct option.
Explanation:
Given that,
M = mass of earth
R = radius of earth
The potential energy at height above the surface of the earth

The kinetic energy at height above the surface of the earth

The total energy at height above the surface of the earth

....(I)
The total energy at the surface of the earth
....(II)
We need to calculate the speed of the object just before it hits Earth
From equation (I) and (II)

Here, h = R


Hence, The speed of the object just before it hits Earth is
.