To determine the net force acting upon an object we need to do the vector addition of the forces acting on it.
In this case we have two forces, one acting to the left and one to the right. We need to establish which of this ways is the positive direction. Let's assume the right direction is the positive direction; for this convention the 20 N forces is positve and the 10 N is positive; then the net force would be:
Since the resulting net force is positive this means, for our convention, that the net force points in the right direction. Therefore, the net force is 10 N to the right.
Electromagnet is<span> a strong, short-lived magnet created by a looped electrical current.
I am sure it is correct! </span>
The answer is Driving long distances
The correct answer to this question is <span>48.8N</span><span> on a bearing of </span><span>134.2 degrees.
In order to solve this, first we need to find the resultant force of the men pulling in the north and south directions:
F = 40 - 6 = 34N [due south - 180]
Then, find the resultant force.
R^2 =34^2 + 35^2
R^2 = 2381
R = sqrt(2381)
R = 44.8N
The angle from the vertical is given by:
tan(x) = 35/34
tan(x) = 1.0294
angle = 45.8 degrees
Taking N as zero degrees, then it bears 134.2 degrees.
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I'm not positive however my guess is this.
KE=(1/2)mv^2
KE=(1/2)(55)(121)
KE=3327.5m/s^2
You might not want to use this tho.