Answer:
ω = ω₀ + α t
ω² = ω₀² + 2 α θ
θ = θ₀ + ω₀ t + ½ α t²
Explanation:
Rotational kinematics can be treated as equivalent to linear kinematics, for this change the displacement will change to the angular displacement, the velocity to the angular velocity and the acceleration to the angular relation, that is
x → θ
v → ω
a → α
with these changes the three linear kinematics relations change to
ω = ω₀ + α t
ω² = ω₀² + 2 α θ
θ = θ₀ + ω₀ t + ½ α t²
where it should be clarified that to use these equations the angles must be measured in radians
Answer:
8.975 m/
Explanation:
Travel starting velocity (u) = 34.8 m/s
Achieved (final) velocity = 214.3 m/s
Travelling time(t) = 20 s
we know that, v =u +at
; where v= final velocity
u=start velocity
a=acceleration
t=time
Therefore,
His acceleration, a = (v-u)/t
=(214.3-34.8)/20
= 8.975 m/
Answer:
It's Helium.
Explanation:
The superficial layers of the star compress the core as an effect of its own gravity. Therefore, atoms will be closer to each other in the core, allowing them to be combined.
A nuclear reaction occurs when light elements combine into heavier elements (that is known as nucleosynthesis). Different ways in which that can happen exist, but the most common in the Sun, according to its mass, is the Proton-Proton chain reaction. In that fusion reaction two atoms of Hydrogen are combined to form Helium.
Remember that a Helium atom is composed of two Protons and two Neutrons.
The Proton-Proton chain works in the following way:
+
=
+
+ 
Two Protons combine each other (
) and one Deuterium (
) is gotten, and one Neutrino (
), and one Positron (
) are emitted from them.
+
=
+ 
A deuterium and Proton combine each other and a Helium three nucleus(
) is gotten, and a gamma ray (
) is emitted.
+
=
+
+ 
Two Helium three nucleus combine and a Helium atom (
) is gotten, and two Protons are emitted.
So, when hydrogen atoms fuse together helium is created.
Answer:
I will assume that “maximum force” implies the constant application of power P = 400 hp (international) to accelerating the vehicle. The force will therefore vary with speed as the vehicle accelerates. I will also assume that all engine energy goes into accelerating the vehicle, rather than rotating elements like its wheels.
In this case the 400 hp (equivalent to 298,280 watts) is applied for time t = 2 seconds. Therefore the kinetic energy of the vehicle is increased by:
ΔKE=Pt=(298,280)(2)=596,560 joules.
The initial kinetic energy is:
KEinitial=12mv2
=(0.5)(1600)(82)=51,200 joules.
Therefore final kinetic energy is:
KEfinal=KEinitial+ΔKE
=51,200+596,560
=647,760 joules
Therefore final vehicle velocity can be found:
KEfinal=12mv2
v=2KEfinalm−−−−−−−−√
=(2)(647,760)1600−−−−−−−−−−−√
= 28.455 m/s
Explanation: