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Harman [31]
3 years ago
5

Read each scenario and then answer the question. Scenario A: 120 J of work is done in 6 s. Scenario B: 160 J of work is done in

8 s. Scenario C: 200 J of work is done in 10 s. Which scenario uses the most power?.
Physics
2 answers:
Alexeev081 [22]3 years ago
4 0

The power in every scenario is the same. Power is the measurement of the energy transfer over time.

<h3>What is power?</h3>

Power is the measurement of the energy transfer over time. It can be calculated by the formula,

P = \dfrac Wt

Where,

P- power

W - work

t - time

In scenario A,

P = \dfrac {120 }6 = 20 \rm \ W

In scenario B,

P = \dfrac {160 }8 = 20 \rm \ W

In scenario B,

P = \dfrac {200 }{10} = 20 \rm \ W

Therefore, the power in every scenario is the same.

Learn more about Power:

brainly.com/question/1618040

Andrej [43]3 years ago
3 0

Answer:

Read each scenario and then answer the question.

Scenario A: 120 J of work is done in 6 s.

Scenario B: 160 J of work is done in 8 s.

Scenario C: 200 J of work is done in 10 s.

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To understand the meaning of the variables that appear in the equations for rotational kinematics with constant angular accelera
Elis [28]

Answer:

   ω = ω₀ + α t

      ω² = ω₀² + 2 α  θ

      θ = θ₀ + ω₀ t + ½ α t²

Explanation:

Rotational kinematics can be treated as equivalent to linear kinematics, for this change the displacement will change to the angular displacement, the velocity to the angular velocity and the acceleration to the angular relation, that is

     x → θ

     v → ω

     a → α

with these changes the three linear kinematics relations change to

      ω = ω₀ + α t

      ω² = ω₀² + 2 α  θ

      θ = θ₀ + ω₀ t + ½ α t²

where it should be clarified that to use these equations the angles must be measured in radians

5 0
3 years ago
Mation about your sour
Ann [662]

(#1). (D).

(#2). (C).

8 0
3 years ago
10.If Zak is traveling at a velocity of 34.8 m/s and he increases his speed to 214.3 m/s over 20
dezoksy [38]

Answer:

8.975 m/s^{2}

Explanation:

Travel starting velocity (u) = 34.8 m/s

Achieved (final) velocity = 214.3 m/s

Travelling time(t) = 20 s  

we know that, v =u +at

                          ; where v= final velocity

                                       u=start velocity

                                       a=acceleration

                                       t=time

Therefore,

       His acceleration,     a = (v-u)/t

                                           =(214.3-34.8)/20

                                           = 8.975 m/s^{2}

6 0
3 years ago
What element is created when hydrogen atoms fuse together in the sun’s core?
Lilit [14]

Answer:

It's Helium.

Explanation:

The superficial layers of the star compress the core as an effect of its own gravity. Therefore, atoms will be closer to each other in the core, allowing them to be combined.

A nuclear reaction occurs when light elements combine into heavier elements (that is known as nucleosynthesis). Different ways in which that can happen exist, but the most common in the Sun, according to its mass, is the Proton-Proton chain reaction. In that fusion reaction two atoms of Hydrogen are combined to form Helium.

Remember that a Helium atom is composed of two Protons and two Neutrons.

The Proton-Proton chain works in the following way:

^{1}H +^{1}H = ^{2}H + \nu + e^{+}

                 

Two Protons combine each other (^{1}H) and one Deuterium (^{2}H)  is gotten, and one Neutrino (\nu), and one Positron (e^{+}) are emitted from them.

       

^{2}H +^{1}H = ^{3}He + \gamma

       

A deuterium and Proton combine each other and a Helium three nucleus(^{3}He) is gotten, and a gamma ray (\gamma) is emitted.

                 

^{3}He +^{3}He = ^{4}He + ^{1}H + ^{1}H

             

Two Helium three nucleus combine and a Helium atom  (^{4}He) is gotten, and two Protons are emitted.

                       

So, when hydrogen atoms fuse together helium is created.

3 0
3 years ago
A 400 hp engine in a 1,600 kg car applies maximum force for 2 seconds to accelerate the car onto the
babymother [125]

Answer:

I will assume that “maximum force” implies the constant application of power  P  = 400 hp (international) to accelerating the vehicle. The force will therefore vary with speed as the vehicle accelerates. I will also assume that all engine energy goes into accelerating the vehicle, rather than rotating elements like its wheels.

In this case the 400 hp (equivalent to 298,280 watts) is applied for time  t  = 2 seconds. Therefore the kinetic energy of the vehicle is increased by:

ΔKE=Pt=(298,280)(2)=596,560  joules.

The initial kinetic energy is:

KEinitial=12mv2

=(0.5)(1600)(82)=51,200  joules.

Therefore final kinetic energy is:

KEfinal=KEinitial+ΔKE

=51,200+596,560

=647,760  joules

Therefore final vehicle velocity can be found:

KEfinal=12mv2

v=2KEfinalm−−−−−−−−√

=(2)(647,760)1600−−−−−−−−−−−√

= 28.455 m/s

Explanation:

4 0
3 years ago
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