Answer:
The third charge placed is 0.80 m.
Explanation:
Given that,
Distance = 0.57 m
First charge = q
Third charge = 2q
We need to calculate the electrostatic force on charge q₁ due to q₂
Using formula of electrostatic force

When placed another charge q₃ at certain distance from origin, then the net force on charge q₁ due to both charges is

The net electrostatic force on the charge at the origin doubles.






Put the value into the formula



Hence, The third charge placed is 0.80 m from origin in x-axis.
Answer:
The toy's energy is 18 J.
Explanation:
We have, a 4 kg toy is lifted off the ground and falls at 3 m/s. It is required to find toy's energy.
The toy will have kinetic energy due to its motion. The energy is given by :

So, the toy's energy is 18 J.
Explanation:
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Answer:
The objects were 1.8m apart.
Explanation:
We will start stating the Coulomb's Law. It says that:

Where F_e is the electric force between the objects, q_1 and q_2 are the magnitude of the charge of the objects, r is the distance between them and K is the Coulomb's constant (
in vacuum). Solving for the distance r we have:

Plugging the given values into this equation, we obtain:

In words, the two charged objects were 1.8m apart.