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olga nikolaevna [1]
3 years ago
11

_____ has the potential to superimpose digital data over real photos so that GPS maps can be combined with real pictures of stor

es and streets to help people locate their position.
Physics
1 answer:
IRISSAK [1]3 years ago
4 0

<u>Augmented reality</u> has the potential to superimpose digital data over real photos so that GPS maps can be combined with real pictures of stores and streets to help people locate their position.

<u>Explanation:</u>

An engaging perception of an original globe atmosphere, where by computer-generated perceptual knowledge the transformation of real-world entities take place and also by multiple sensory modalities, involving somatosensory, visual, auditory, haptic and olfactory forms, thus known as augmented reality.

AR app uses GPS and camera from a smartphone to deploy an augmented reality-enabled GPS navigation system. As in the web, AR tool termed as Real View Navigation is accessible to all Android and iOS clients. Google is brought its first virtual reality walking directions, now recognized as Live Experience on Google Maps.

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With its wheels locked, a van slides down a hill inclined at 40.0° to the horizonta l. Find the acceleration of this van A) if t
andreyandreev [35.5K]

Answer:

Explanation:

Check attachment for solution

7 0
4 years ago
A charge +q is located at the origin, while an identical charge is located on the x axis at x = +0.57 m. A third charge of +2q i
Jlenok [28]

Answer:

The third charge placed is 0.80 m.

Explanation:

Given that,

Distance = 0.57 m

First charge = q

Third charge = 2q

We need to calculate the electrostatic force on charge q₁ due to q₂

Using formula of electrostatic force

F_{21}=\dfrac{kq_{1}q_{2}}{r_{1}^2}

When placed another charge q₃ at certain distance from origin, then the net force on charge q₁ due to both charges is

F_{net}=F_{21}+F_{31}

The net electrostatic force on the charge at the origin doubles.

2F_{21}=F_{21}+F_{31}

F_{31}=F_{21}

\dfrac{kq_{3}q_{1}}{r_{2}^2}=\dfrac{kq_{2}q_{1}}{r_{1}^2}

\dfrac{q_{3}}{r_{2}^2}=\dfrac{q_{2}}{r_{1}^2}

r_{2}^2=\dfrac{q_{3}}{q_{2}\timesr_{1}^2}

r_{2}=\sqrt{\dfrac{q_{3}}{q_{2}}}r_{1}

Put the value into the formula

r_{2}=\sqrt{\dfrac{2q}{q}}\times0.57

r_{2}=\sqrt{2}\times0.57

r_{2}=0.80\ m

Hence, The third charge placed is 0.80 m from origin in x-axis.

4 0
3 years ago
Q7:<br> A 4 kg toy is lifted off the ground and falls at 3 m/s. What is the toy's energy?
alexandr1967 [171]

Answer:

The toy's energy is 18 J.

Explanation:

We have, a 4 kg toy is lifted off the ground and falls at 3 m/s. It is required to find toy's energy.

The toy will have kinetic energy due to its motion. The energy is given by :

E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\times 4\times 3^2\\\\E=18\ J

So, the toy's energy is 18 J.

7 0
3 years ago
How much more matter is in a golf ball than a ping pong?
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Explanation:

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3 0
3 years ago
Scientists experimenting with two charged objects of 2.56 x 10-6 C and 3.34 x 10-7 C displayed a repulsion of 2.26 x 10-3 N. How
Pachacha [2.7K]

Answer:

The objects were 1.8m apart.

Explanation:

We will start stating the Coulomb's Law. It says that:

F_e=\frac{Kq_1q_2}{r^{2}}

Where F_e is the electric force between the objects, q_1 and q_2 are the magnitude of the charge of the objects, r is the distance between them and K is the Coulomb's constant (K=8.9*10^{9} \frac{Nm^{2} }{C^{2} } in vacuum). Solving for the distance r we have:

r=\sqrt{\frac{Kq_1q_2}{F_e} }

Plugging the given values into this equation, we obtain:

r=\sqrt{\frac{(8.9*10^{9}\frac{Nm^{2} }{C^{2} })(2.56*10^{-6}C)(3.34*10^{-7}C)}{2.26*10^{-3}N}}=1.8m

In words, the two charged objects were 1.8m apart.

6 0
3 years ago
Read 2 more answers
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