All categories

3 years ago

Which of the following statements is correct?

Physics

1 answer:

Mumz [18]3 years ago

7 0

Answer: c. Generally, metals are ductile.

Explanation:

From the options given in the question, the correct statement is that"Generally, metals are ductile.

Ductility of a metal simply means that a metal can be plastically deform before it is then fractured. It implies that metals can be drawn to thin wires. The only exception we have in this case is mercury.

You might be interested in

Which of the following is NOT a symptom associated with hypertension?

zepelin [54]

I would say a or d hope this helps haha ( also if you could do brainliest for this that would be AMASINF bc I really want to rank up, u don’t have to tho)

8 0

3 years ago

Read 2 more answers

In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th

diamong [38]

Answer:

3.77 Hz

Explanation:

The beat frequency that is heard can be calculated using the following equation:

$f_{b} = f_{1} - f_{2}$

Where:

f₁ = 110 Hz

$f_{2} = \frac{f_{1}}{\sqrt{\frac{T_{1}}{T_{2}}}}$

With:

T₁ = 594 N

T₂ = 554 N

$f_{2} = \frac{f_{1}}{\sqrt{\frac{T_{1}}{T_{2}}}} = \frac{110 Hz}{\sqrt{\frac{594 N}{554 N}}} = 106.23 Hz$

Hence, the beat frequency is:

$f_{b} = f_{1} - f_{2} = 110 Hz - 106.23 Hz = 3.77 Hz$

Therefore, the beat frequency that is heard when the hammer strikes the two strings simultaneously is 3.77 Hz.

I hope it helps you!

3 0

4 years ago

Horse begin running due east and covered 25 km in four hours what is the average of the velocity of the horse

Andrei [34K]

Average velocity = (displacement) / (time)

Displacement = distance and direction between start and end points

Displacement = 25 km east

Average velocity = (25 km east) / (4 hours)

Average velocity = 6.25 km/hr east

7 0

3 years ago

Once a player catches the Frisbee they are only allowed to pivot like in

Natasha_Volkova [10]

True I know from pe hahahahha

5 0

3 years ago

Read 2 more answers

X-rays with an energy of 400 keV undergo Compton scattering with a target. If the scattered X-rays are detected at \theta = 30^{

marissa [1.9K]

Answer:

37.91594 keV

Explanation:

$E_i$ = Incident energy = 400 keV

θ = 30°

h = Planck's constant = 4.135×10⁻¹⁵ eV s = 6.626×10⁻³⁴ J s

Incident photon wavelength

$\lambda_i=\frac{hc}{E_i}\\\Rightarrow \lambda_i=\frac{4.135\times 10^{-15}\times 3\times 10^8}{400\times 10^3}\\\Rightarrow \lambda_i=3.101\times 10^{-12}\ m$

Difference in wavelength

$\Delta \lambda=\frac{h}{m_ec}(1-cos\theta)\\\Rightarrow \Delta \lambda=\frac{6.626\times 10^{-34}}{9.11\times 10^{-31}\times 3\times 10^8}(1-cos30)\\\Rightarrow \Delta \lambda=3.248\times 10^{-13}\ m$

$\lambda_f=\lambda_i+\Delta \lambda\\\Rightarrow \lambda_f=3.101\times 10^{-12}+3.248\times 10^{-13}\\\Rightarrow \lambda_f=3.426\times 10^{-12}$

Final photon wavelength

$\lambda_f=\frac{hc}{\lambda_f}\\\Rightarrow E_f=\frac{4.135\times 10^{-15}\times 3\times 10^8}{3.426\times 10^{-12}}\\\Rightarrow E_f=362084.06\ eV = 362.08406\ keV$

Energy of the recoiling electron

$\Delta E=E_i-E_f\\\Rightarrow \Delta E=400-362.08406=37.91594\ keV$

Energy of the recoiling electron is 37.91594 keV

8 0

4 years ago

Read 2 more answers