Answer:
v = 4.18 m/s
Explanation:
given,
frequency of the alarm = 872.10 Hz
after passing car frequency she hear = 851.10 Hz
Speed of sound = 343 m/s
speed of the jogger = ?
speed of the
![v_f = \dfrac{872.10-851.10}{2}](https://tex.z-dn.net/?f=v_f%20%3D%20%5Cdfrac%7B872.10-851.10%7D%7B2%7D)
![v_f =10.5\ Hz](https://tex.z-dn.net/?f=v_f%20%3D10.5%5C%20Hz)
v_o = 872.1 - 10.5
![V_0 = 861.6\ Hz](https://tex.z-dn.net/?f=V_0%20%3D%20861.6%5C%20Hz)
The speed of jogger
![v = \dfrac{v_1 \times 343}{v_0}-343](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7Bv_1%20%5Ctimes%20343%7D%7Bv_0%7D-343)
![v = \dfrac{872.1 \times 343}{861.6}-343](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B872.1%20%5Ctimes%20343%7D%7B861.6%7D-343)
v = 4.18 m/s
All of the elements in a period have the same number of atomic orbitals. For example, every element in the top row (the first period) has one orbital for its electrons. All of the elements in the second row (the second period) have two orbitals for their electrons. As you move down the table, every row adds an orbital.
Answer:
Explanation:
We shall apply Stefan's formula
E = AσT⁴
When T = 300
I₁ = Aσ x 300⁴
When T = 400K
I₂ = Aσ x 400⁴
I₂ / I₁ = 400⁴ / 300⁴
= 256 / 81
= 3.16
I₂ = 3.16 I₁ .
Straight
You already have to momentum of walking forward, and going back and forth are the same distance. If you go back then you would have to stop, turn and walk, but if you go forward you just have to walk.
The energy carried by a single photon of frequency f is given by:
![E=hf](https://tex.z-dn.net/?f=E%3Dhf)
where
![h=6.6 \cdot 10^{-34} m^2 kg s^{-1}](https://tex.z-dn.net/?f=h%3D6.6%20%5Ccdot%2010%5E%7B-34%7D%20m%5E2%20kg%20s%5E%7B-1%7D)
is the Planck constant. In our problem, the frequency of the photon is
![f=7.15 \cdot 10^{14}Hz](https://tex.z-dn.net/?f=f%3D7.15%20%5Ccdot%2010%5E%7B14%7DHz)
, and by using these numbers we can find the energy of the photon: