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tensa zangetsu [6.8K]
2 years ago
8

A sample of gold has a mass of 30.94 grams and density of 19.32g/cm^3. What volume of space will this sample of gold occupy?

Physics
2 answers:
sdas [7]2 years ago
6 0
Data:
mass, m = 30.94 g
density, d = 19.32 g/cm^3

Formula: d = m / v => v = m / d = 30.94 g / 19.32 g/cm^3 = 1.60 cm^3

Then, the answer is the option C. 
Brums [2.3K]2 years ago
6 0

Answer:

1.   0.07

2.    1.15

Explanation:

plzz make brainliest

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Explanation:

That is why the cell needs to be small

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The technology in which parabolic mirror arrays are placed in a desert with a water-filled pipe traversing the array is used to
andriy [413]

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3 years ago
A rare and valuable antique chest is being moved into a truck using a 4.00 m long ramp. the kj weight of the chest plus packing
Lisa [10]

First let us calculate for the angle of inclination using the sin function,

sin θ = 1 m / 4 m

θ = 14.48°

 

Then we calculate the work done by the movers using the formula:

W = Fnet * d

 

So we must calculate for the value of Fnet first. Fnet is force due to weight minus the frictional force.

Fnet = m g sinθ – μ m g cosθ

Fnet = 1,500 sin14.48 – 0.2 * 1,500 * cos14.48

Fnet = 84.526 N

 

So the work exerted is equal to:

W = 84.526 N * 4 m

<span>W = 338.10 J</span>

7 0
3 years ago
A charge of 19 nC is uniformly distributed along a straight rod of length 15 m that is bent into a circular arc with a radius of
Salsk061 [2.6K]

Answer:

The magnitude of the electric field at the center of curvature of the arc is 3.87 N/C

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Please see the attachments below

8 0
3 years ago
Un protón se acelera por una diferencia de potencial de 2.6k V y se dirige a una región donde existe un campo magnético uniforme
Bond [772]

Answer:

5.08*10^{-13}N

Explanation:

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The magnitude of the magnetic force will be:

F=qvB=(1.6*10^{-19}C)(705835.3m/s)(4.5T)=5.08*10^{-13}N

hope this helps!

7 0
3 years ago
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