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tensa zangetsu [6.8K]
3 years ago
8

A sample of gold has a mass of 30.94 grams and density of 19.32g/cm^3. What volume of space will this sample of gold occupy?

Physics
2 answers:
sdas [7]3 years ago
6 0
Data:
mass, m = 30.94 g
density, d = 19.32 g/cm^3

Formula: d = m / v => v = m / d = 30.94 g / 19.32 g/cm^3 = 1.60 cm^3

Then, the answer is the option C. 
Brums [2.3K]3 years ago
6 0

Answer:

1.   0.07

2.    1.15

Explanation:

plzz make brainliest

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An airplane accelerates from rest down a runway at 3.20 m/s2 for 32.8 seconds until it lifts off the ground. Determine the dista
vagabundo [1.1K]

Answer:

s=1721.344m  ,v=104.96m/s.

Explanation:

using thr equation of motion;

s=ut+\frac{1}{2}at^{2}

u=0, plane starts from rest,

s=\frac{1}{2}at^{2}

a=3.2m/s^{2}, t=32.8s \\ s=\frac{1}{2}*3.2*32.8^{2}

s=1721.344m

v=u+at

v=0 +3.2*32.8

v=104.96m/s

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3 light-years =________.
KATRIN_1 [288]

               ( 3 yr) · (186,282.397 mile/s) · (86,400 s/day) · (365 day/yr)

           =  (3 · 186,282.397 · 86,400 · 365)  mile

           =      1.762380502 x 10¹³  miles

           =      1.8 x 10¹³  miles    (rounded to the nearest trillion miles)
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A car drives 20 miles north and then 3 miles south. what is the displacement or the car
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Read 2 more answers
an airplane is flying through a thundercloud at a height of 2000m (this is very dangerous thing to do because of updrafts, turbu
Vedmedyk [2.9K]

Answer

In this question we have given,

Height of plane, h1=2000m

Height at which charge concentration is 40C, h2=3000m

Height at which charge concentration is -40C, h3=1000m

charge concentaration, q1=40C

charge concentaration, q2=-40C

let the charge concentrations at height h2 and h3 as point charges

Now we will first find the electric feild on plane due to positive charge q1=40

E1= k*q1/(h1-h2)..............(1)

Here k=8.98755*10^9N.m^2/C^2

q1=40C

put values of k, q1 , h1 and h2 in equation 1


[tex]E1=(8.98755*10^9)*(40)/(2000-3000)^2\\

E1=[tex]E= 359502+359502\\E=719004 V/mV/m[/tex]

similarly electric feild due to negative charge q2=-40

[tex]E2=(8.98755*10^9)*(-40)/(2000-1000)^2\\

E2=359502V/m

Total electric feild E at the aircraft is given as

E= E1+ E2\\...............(2)

Put values of  E1 and E2 in equation2

\\E=359502+359502\\E= 719004V/m\\

therefore s Total electric feild E at the aircraft is E= 719004V/m

3 0
3 years ago
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