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Excess reactant : Na
NaCl produced : = 16.497 g
<h3>Further explanation</h3>
Given
Reaction(balanced)
2Na + Cl₂⇒ 2NaCl
20 g Na
10 g Cl₂
Required
Excess reactant
NaCl produced
Solution
mol Na(Ar = 23 g/mol) :
= 20 : 23 = 0.87
mol Cl₂(MW=71 g/mol):
= 10 : 71 g/mol = 0.141
mol : coefficient :
Na = 0.87 : 2 = 0.435
Cl₂ = 0.141 : 1 = 0.141
Limiting reactant : Cl₂(smaller ratio)
Excess reactant : Na
Mol NaCl based on mol Cl₂, so mol NaCl :
= 2/1 x mol Cl₂
= 2/1 x 0.141
= 0.282
Mass NaCl :
= 0.282 x 58.5 g/mol
= 16.497 g
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I hope this helps.
Answer:
Option B. Sodium
Explanation:
In the formation of NaCl, sodium loses and electron while chlorine receives the electron as illustrated below:
Na —> Na+ + e- ....... (1)
Cl + e- —> Cl- ......... (2)
Now, combining equation 1 and 2 we have:
Na + Cl + e- —> Na+ + Cl- + e-
Cancelling the electron from both side, we obtained:
Na + Cl —> Na+Cl-
From the above illustration, we see clearly that sodium loses electron
Answer: Develop and use a model to describe why asexual reproduction results in offspring with identical ... Statement: Emphasis is on using models such as Punnett squares, diagrams, ... 2. Because both parents are likely to contribute different genetic information, offspring.
Explanation: I hoped that helped!