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worty [1.4K]
3 years ago
11

If you have 110.0 grams of an unknown compound that contains 12.3 grams of hydrogen, what is the percent by mass of hydrogen in

the compound
Chemistry
2 answers:
Vladimir [108]3 years ago
8 0
All you have to do is a simple division "parts over the whole"

12.3 grams H/ 110 grams compound x 100= 11.2%
tankabanditka [31]3 years ago
3 0

Answer : The percent by mass of hydrogen in the compound is, 11.18 %

Explanation : Given,

Mass of unknown compound = 110.0 g

Mass of hydrogen = 12.3 g

Now we have to calculate the percent by mass of hydrogen in the compound.

\text{Mass percent of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Total mass of unknown compound}}\times 100

Now put all the given values in this formula, we get:

\text{Mass percent of hydrogen}=\frac{12.3g}{110g}\times 100

\text{Mass percent of hydrogen}=11.18\%

Therefore, the percent by mass of hydrogen in the compound is, 11.18 %

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Answer:

<em>D. One negative charge</em>

Explanation:

During the formation of a bond, if an atom gains an electron, after that it will be left with a negative charge compared to the atom before the bond is formed. This is because in these types of bonds, which are <em>ionic bonds</em>, there is a <em>transfer of electrons between atoms</em>, there will be one or more atoms that yield electrons that will be captured by another and other atoms that gain them, and the difference of charges produced by this transfer of electrons, will cause the union to occur due to the attraction between electrostatic forces.

If you have a neutral atom before joining, and it gains an electron to form a bond,<em> it will have one electron more than its initial state</em> (in the initial state, the number of protons and electrons is the same, because the atoms they are electrically neutral), so having an extra electron will make it have a negative charge, since there will be a difference between the number of protons and electrons that the atom possesses. <em>This is why the correct answer is D. </em>

In the case of <em>response A and B</em>, <em>the atom could only remain positively charged if it loses electrons</em>, but as in this case it wins, <em>they are not correct</em>.

<em>The answer C is also not correct</em> because only one electron wins, so that it is left with two negative charges, <em>it should gain two electrons during the bond formation.</em>

7 0
3 years ago
When rocks grind and squeeze past each other,___metamorphism occur.
dangina [55]

Answer:

Dynamic

Explanation:

When rocks grind and squeeze past each other, dynamic metamorphism can occur.

6 0
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When 0.25 moles of NH3 are produced according to the reaction below, how many moles of H2 must have reacted?
marissa [1.9K]

Answer:

Explanation:

by stoichiometry

nNH3/2=nH2/3

0.25/2=nH2/3

nH2=0.25×3/2

nH2=0.375 mol

so its 0.38 mol

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Describe radiation in a full sentence
Mandarinka [93]

Answer:

Radiation is energy that comes from a source and travels through space at the speed of light.

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3 years ago
For the equilibrium PCl5(g) PCl3(g) + Cl2(g), Kc = 2.0 × 101 at 240°C. If pure PCl5 is placed in a 1.00-L container and allowed
Cloud [144]

Answer:

the equilibrium concentration of [PCl₅] is 3.64*10⁻³ M

Explanation:

for the reaction

PCl₅(g) → PCl₃(g) + Cl₂(g)

where

Kc= [PCl₃]*[Cl₂]/[PCl₅] = 2.0*10¹ M = 20 M

and [A] denote concentrations of A

if initially the mixture is pure PCl₅ , then it will dissociate according to the reaction and since always one mole of PCl₃(g) is generated with one mole of Cl₂(g) , the total number of moles of both at the end is the same → they have the same concentration → [PCl₃(g)] = [Cl₂]=0.27 M

therefore

Kc= [PCl₃]*[Cl₂]/[PCl₅] = 0.27 M* 0.27 M /[PCl₅] = 20 M

[PCl₅]  =  0.27 M* 0.27 M / 20 M = 3.64*10⁻³ M

[PCl₅]  = 3.64*10⁻³ M

the equilibrium concentration of [PCl₅] is 3.64*10⁻³ M

6 0
3 years ago
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