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Pavel [41]
3 years ago
8

Use the periodic table to answer the questions below.

Chemistry
2 answers:
MrRa [10]3 years ago
4 0

Answer:

Second option.

Explanation:

Nitrogen is the first element of group 15, and its number atomic is 7, so, in its neutral state, it has 7 electrons.

By Linus Pauling diagram (see figure), the electronic distribution will be:

1s^{2} 2s^{2} 2p^{3}

The distribution follows the arrows, from the less energetic subshell for the most energetic one. The subshell <em>s</em> has an only magnetic number, so only one orbital to put electrons. Subshell <em>p</em> has 3 magnetic numbers, so 3 orbitals to put electrons.

To put the electrons, we have to follow Hund's Rule: fulfill the orbitals which only one<em> spin</em>, until all orbitals have this <em>spin</em>, so continue, with the other <em>spin</em>, until finishing the electrons on that subshell. <em>Spin</em> is the rotation of the electron, and it can be +1/2 or -1/2.

So, for subshell 2p, how there are only 3 electrons, all three will be put with the same <em>spin</em> (+1/2, up arrow). If there was one more electron, it would be filled in the first orbital with the <em>spin</em> -1/2, down arrow.

Romashka-Z-Leto [24]3 years ago
3 0
B ............ is the answer,
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Calculate how many grams of the first reactant are necessary to completely react with 17.3 g of the second reactant. the reactio
soldier1979 [14.2K]

Taking into account the reaction stoichiometry, 16.611 grams of Na₂CO₃ are necessary to completely react with 17.3 g of CuCl₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Na₂CO₃ + CuCl₂  → CuCO₃ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • CuCl₂: 1 mole
  • CuCO₃: 1 mole
  • NaCl: 2 moles

The molar mass of the compounds is:

  • Na₂CO₃: 129 g/mole
  • CuCl₂: 134.45 g/mole
  • CuCO₃: 123.55 g/mole
  • NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Na₂CO₃: 1 mole ×129 g/mole= 129 grams
  • CuCl₂: 1 mole ×134.45 g/mole= 134.45 grams
  • CuCO₃: 1 mole ×123.55 g/mole= 123.55 grams
  • NaCl: 2 mole ×58.45 g/mole=116.9 grams

<h3>Mass of CuCl₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 134.35 grams of CuCl₂ react with 129 grams of Na₂CO₃, 17.3 grams of CuCl₂ react with how much mass of Na₂CO₃?

mass of Na₂CO₃= (17.3 grams of CuCl₂× 129 grams of Na₂CO₃)÷ 134.35 grams of CuCl₂

<u><em>mass of Na₂CO₃= 16.611 grams</em></u>

Finally, 16.611 grams of Na₂CO₃ is required.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

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