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Sergeeva-Olga [200]
3 years ago
12

How many liters of water can be formed if 1.65 liters of ethylene are consumed

Chemistry
1 answer:
alexandr1967 [171]3 years ago
4 0
Ethylene Burns in the presence of O₂ to produce CO₂ and H₂O vapors;

                               C₂H₄  +  3 O₂   →   2 CO₂  +  2 H₂O

According to equation, 

22.4 L (1 mole) C₂H₄ reacts completely to produce  =  44.8 L (2 moles) of H₂O

So, 

1.65 L of C₂H₄ on complete reaction will produce  =  X L of H₂O

Solving for X,

                                  X  =  (1.65 L × 44.8 L) ÷ 22.4 L

                                  X  =  3.3 L of H₂O
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Find the area shaded in yellow.<br> [ ? ] square units
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Answer:

A(yellow) = 52

Explanation:

A(yellow) = A(total) - A(red)

= 11×6 - 7×2

= 66 - 14

= 52

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Which of the answer choices correctly identifies a scenario that displays evidence a chemical reaction is occurring?
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What is mars average distance from the sun
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3 years ago
Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop
Reil [10]

Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

                     Mg  +   Cu(NO₃)₂    ⇒    Mg(NO₃)₂   +   Cu

                  Reactants           Elements            Products

                         1                          Mg                     1

                         1                          Cu                      1

                         2                          N                       2

                         6                          O                       6

Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

                                              = 24 + 28 + 96

                                              = 148 g

                           24 g of Mg  --------------------  148 g of Mg(NO₃)₂

                          147.4 g of Mg -------------------   x

                            x = (147.4 x 148) / 24

                            x = 908.96 g of Mg(NO₃)₂

2.- Calculate the Actual yield

yield percent = \frac{actual yield}{theoretical yield}

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = \frac{30.8}{100} x 908.96

Actual yield = 279.95 ≈ 280g

                     

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