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Sergeeva-Olga [200]
3 years ago
12

How many liters of water can be formed if 1.65 liters of ethylene are consumed

Chemistry
1 answer:
alexandr1967 [171]3 years ago
4 0
Ethylene Burns in the presence of O₂ to produce CO₂ and H₂O vapors;

                               C₂H₄  +  3 O₂   →   2 CO₂  +  2 H₂O

According to equation, 

22.4 L (1 mole) C₂H₄ reacts completely to produce  =  44.8 L (2 moles) of H₂O

So, 

1.65 L of C₂H₄ on complete reaction will produce  =  X L of H₂O

Solving for X,

                                  X  =  (1.65 L × 44.8 L) ÷ 22.4 L

                                  X  =  3.3 L of H₂O
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there is an ice cream shop 6 blocks north of your hotel. how many minutes will it take to walk there and back
Allushta [10]

Answer:

This question is incomplete

Explanation:

This question is incomplete.

However, when all the required data are available, you can use the formula/steps below

Average speed/velocity (m/s) = distance (in metres) ÷ time (in seconds)

Time (in secs) = distance ÷ average speed/velocity

Kindly note that "blocks" is not a standard unit for distance measurement in science, hence the distance (since its a walking distance) must be in metres (or converted to metres if not in metres).

The distance in the formula is the distance from the hotel to the ice cream shop while the average speed is the distance covered per time as s/he walks to the ice cream shop and back. Hence, the answer gotten from the formula above will have to be multiplied by 2 (in order to get the time taken to walk to the ice cream shop and back) because the formula will only provide answer to one trip (time taken to walk to the shop).

After the multiplication mentioned above, the time in seconds should be converted to minutes by dividing the answer in seconds by 60

8 0
3 years ago
one kilogram of water (V1 = 1003 cm^3*kg-1) in a piston cylinder device at (25°C) and 1 bar is compressed in a mechanically reve
vova2212 [387]

Answer:

Q = -18118.5KJ

W = -18118.5KJ

∆U = 0

∆H = 0

∆S = -60.80KJ/KgK

Explanation:

W = RTln(P1/P2)

P1 = 1bar = 100KN/m^2, P2 = 1500bar = 1500×100 = 150000KN/m^2, T = 23°C = 23 + 273K = 298K

W = 8.314×298ln(100/150000) = 8.314×298×-7.313 = -18118.5KJ ( work is negative because the isothermal process involves compression)

∆U = Cv(T2 - T1)

For an isothermal process, temperature is constant, so T2 = T1

∆U = Cv(T1 - T1) = Cv × 0 = 0

Q = ∆U + W = 0 + (-18118.5) = 0 - 18118.5 = -18118.5KJ

∆H = Cp(T2 - T1)

T2 = T1

∆H = Cp(T1 - T1) = Cp × 0 = 0

∆S = Q/T

Mass of water = 1kg

Heat transferred (Q) per kilogram of water = -18118.5KJ/Kg

∆S = (-18118.5KJ/Kg)/298K = -60.80KJ/KgK

4 0
3 years ago
How many microliters are in 0.68 liters? 
kolezko [41]

There are 680,000 microliters in 0.68 liters.

8 0
3 years ago
As you have seen in this lab, the density of water is near 1 g/cm3. Anything with a density lower than this will float in water,
hammer [34]
The third answer is the one you want. You have to have an adjustable density. All other things being equal, if the tanks you use for holding just water when filled with water will let the sub sink, because the sub is made of a dense metal like iron or steel.

If on the other hand you fill these tanks with air, the net density will be below one and the sub will rise.
8 0
3 years ago
Read 2 more answers
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Cloud [144]

Answer:i really know it is 29.09

Explanation:

8 0
3 years ago
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