All categories

4 years ago

How many liters of water can be formed if 1.65 liters of ethylene are consumed

1 answer:

alexandr1967 [171]4 years ago

4 0

Ethylene Burns in the presence of O₂ to produce CO₂ and H₂O vapors;

C₂H₄ + 3 O₂ → 2 CO₂ + 2 H₂O

According to equation,

22.4 L (1 mole) C₂H₄ reacts completely to produce = 44.8 L (2 moles) of H₂O

So,

1.65 L of C₂H₄ on complete reaction will produce = X L of H₂O

Solving for X,

X = (1.65 L × 44.8 L) ÷ 22.4 L

X = 3.3 L of H₂O

You might be interested in

What’s the molar mass of Lead-208

Degger [83]

Lead is a basic metal and almost 11 isotopes of Lead are reported. The isotopes with greater natural abundance are as follow;

1) ²⁰⁸Pb with abundance 52.4 %

2) ²⁰⁶Pb with abundance 24.1 %

3) ²⁰⁷Pb with abundance 22.1 %

4) ²⁰⁴Pb with abundance 1.4 %

Molar mass of ²⁰⁸Pb:

Molar mass of any element is the total of number of protons, neutrons and electrons.
As, number of protons in Lead are 82 then in ²⁰⁸Pb isotope number of neutrons are...

# of Neutrons = M.mass - # of protons

# of Neutrons = 208 - 82

# of Neutrons = 126

Result:

Molecular Mass of Lead (²⁰⁸Pb) is 208 amu.

# of Protons in ²⁰⁸Pb = 82

# of Neutrons in ²⁰⁸Pb = 126

7 0

3 years ago

Particle 1 has a velocity v1 = 2 m/s and a mass m1 = 2 kg . this particle collides with particle 2 of mass m2 = 6 kg , which is

creativ13 [48]

This follows the law of conservation of momentum. Momentum is the product of mass and velocity of object.
Momentum = mass(m) x velocity(v)
law of conservation of momentum means that the total momentum of system before the collision of 2 objects is equal to the total momentum after the collision
Before the collision total momentum
= m1v1 + m2v2
m1 = 2 kg
v1 = 2 m/s
m2 = 6 kg
v2 = 0 m/s
substituting the values in the equation
total momentum before = (2 kg x 2 m/s) + (6 kg x 0 m/s)
total momentum = 4 kgm/s
after the collision the 2 objects stick together and have a common velocity
total momentum after the collision = (6 kg + 2 kg)x V = 8V
V = speed of the conglomerate particle

since total momentum before is equal to total momentum after
8V = 4
V = 2 m/s
speed of conglomerate particle is 2 m/s

8 0

3 years ago

Why are red dwarfs not able to fuse helium to heavier elements?

ohaa [14]

Fusing helium into heavier elements requires extreme pressure and temperature. However red dwarfs' gravity is simply not enough to bring helium atom close enough to each other for fusion to occur. Therefore, red dwarfs not able to fuse helium to heavier elements.☺

7 0

4 years ago

Assuming the volumes are additive, what is the [Cl−] in a solution obtained by mixing 297 mL of 0.675 M KCl and 664 mL of 0.338

Elden [556K]

Answer: The concentration of chloride ions in the solution obtained is 0.674 M

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For KCl:

Molarity of KCl solution = 0.675 M

Volume of solution = 297 mL

Putting values in equation 1, we get:

$0.675=\frac{\text{Moles of KCl}\times 1000}{297}\\\\\text{Moles of KCl}=\frac{(0.675mol/L\times 297)}{1000}=0.200mol$

1 mole of KCl produces 1 mole of chloride ions and 1 mole of potassium ion

Moles of chloride ions in KCl = 0.200 moles

For magnesium chloride:

Molarity of magnesium chloride solution = 0.338 M

Volume of solution = 664 mL

Putting values in equation 1, we get:

$0.338=\frac{\text{Moles of }MgCl_2\times 1000}{664}\\\\\text{Moles of }MgCl_2=\frac{(0.338mol/L\times 664)}{1000}=0.224mol$

1 mole of magnesium chloride produces 2 moles of chloride ions and 1 mole of magnesium ion

Moles of chloride ions in magnesium chloride = $(2\times 0.224)=0.448mol$

Calculating the chloride ion concentration, we use equation 1:

Total moles of chloride ions in the solution = (0.200 + 0.448) moles = 0.648 moles

Total volume of the solution = (297 + 664) mL = 961 mL

Putting values in equation 1, we get:

$\text{Concentration of chloride ions}=\frac{0.648mol\times 1000}{961}\\\\\text{Concentration of chloride ions}=0.674M$

Hence, the concentration of chloride ions in the solution obtained is 0.674 M

5 0

3 years ago

What would be another property that we Earthlings could use to classify stars?

Blizzard [7]

Answer: At the point when space experts take a gander at an article's range, they can decide its arrangement dependent on these frequencies. The most well-known technique stargazers use to decide the sythesis of stars, planets, and different articles is spectroscopy. This spread-out light is known as a range.

Explanation:

8 0

4 years ago