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asambeis [7]
3 years ago
5

ammonia (NH3(g) Hf=-45.9 kJ/mol) reacts. with oxygen to produce nitrogen and water (H2O(g) Hf = -241.8 kJ/mol according to the e

quation below. 4NH3(g) + 3O2(g)---> 2N2(g) +6H2O(g) what is the enthalpy of the reaction
Chemistry
2 answers:
weeeeeb [17]3 years ago
8 0

Answer:The answer given is 100% correct. I think kids are just looking at the wrong problem thats why it has a 2 star.. B is correct

Explanation:edge 2020

kherson [118]3 years ago
6 0

Answer:

ΔH°_rxn = -195.9 kJ·mol⁻¹

Explanation:

                              4NH₃(g) + 3O₂(g) ⟶ 2N₂(g) +6H₂O(g)

ΔH°_f/(kJ·mol⁻¹):    -45.9          0                 0        -241.8

The formula relating ΔH°_rxn and enthalpies of formation (ΔH°_f) is

ΔH°_rxn = ΣΔH°_f(products) – ΣΔH°_f(reactants)

ΣΔH°_f(products) = -6(241.8) = -1450.8 kJ

ΣΔH°_f(reactants) = -4(45.9) = -183.6 kJ

ΔH°_rxn =  (-1450.8 + 183.6) kJ = -1267.2 kJ

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