Question

70 points and will give brainliest

Answer 1

Answer:

74mL

Explanation:

Given parameters:

Molar mass of citric acid = 192g/mol

Molar mass of baking soda = 84g/mol

Concentration of citric acid  = 0.8M

Mass of baking powder = 15g

Unknown parameters:

Volume of citric acid = ?

Solution

       Equation of the reaction:

            C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Procedure:

• We work from the known parameters to the unknown. From the statement of the problem, we can approach the solution from the parameters of the baking powder.
• From the baking powder, we can establish a molar relationship between the two reactants. We employ the mole concept in this regard.
• We find the number of moles of the baking powder that went into the reaction using the expression below:

                Number of moles = $\frac{mass}{molar mass}$

                Number of moles =  $\frac{15}{84}$ = 0.179mole

• From the equation of the reaction, we can find the number of moles of the citric acid:

             3 moles of baking powder reacted with 1 mole of citric acid

 0.179 moles of baking powder would react with $\frac{0.179}{3}$:

          This yields 0.059mole of citric acid

• To find the volume of the citric acid, we use the mole expression below:

    Volume of citric acid = $\frac{number of moles}{concentration}$

Volume of citric acid = $\frac{0.059}{0.8}$ = 0.074L

Expressing in mL gives 74mL