Classification systems are mental models that we create to make sorting things simpler and more efficient. We make compromises to emphasize certain details and hide others based on their perceived relevance to achieving the outcomes we seek. Even if the original model was nearly perfect, you should expect the inputs provided and outcomes desired to change as time goes by.
In time, we usually find that we have over-simplified by ignoring important details. Mental models such as classification systems should evolve over time. This enables them to more accurately reflect reality and lead to the outcomes we seek.
You can only find the details you seek by observing the right layer of abstraction.
Answer : The value of equilibrium constant for this reaction at 328.0 K is 
Explanation :
As we know that,
where,
= standard Gibbs free energy = ?
= standard enthalpy = 151.2 kJ = 151200 J
= standard entropy = 169.4 J/K
T = temperature of reaction = 328.0 K
Now put all the given values in the above formula, we get:
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = 95636.8 J
R = gas constant = 8.314 J/K.mol
T = temperature = 328.0 K
K = equilibrium constant = ?
Now put all the given values in the above formula, we get:
Therefore, the value of equilibrium constant for this reaction at 328.0 K is
Here you are looking on the Free Body diagram of a net force of 0N in both the x and y-directions. the only ones that has that condition met is A and C.
Glucose is a simple sugar with the molecular formula C6H12O6. It is a carbohydrate.
