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Semenov [28]
3 years ago
15

What is the total number of valence electrons un xenon(xe)

Chemistry
1 answer:
Ber [7]3 years ago
6 0

Answer:

8

Explanation:

Hope this helps you :)

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How long in hours would it take a runner to finish an 11 km race if she is running at a pace of 5.7 mi/hr?
Alenkinab [10]

It would take 1.16 h for the runner to finish the race .

<em>Step 1. </em>Convert <em>kilometres to miles</em>.

11 km × (0.621 mi/1 km) = 6.83 mi

<em>Step 2</em>. Calculate the <em>time</em>.

Time = 6.83 mi × (1 h/5.7 mi) = 1.16 h

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<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

45.6 g Au ( 1 mol / 196.97 g ) (  </span>6.022 x 10^23 atoms / mole ) = 1.39x10^23 atoms Au
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Scientists have changed the model of the atom as they have gathered new evidence. One of the atomic models is shown below. A pur
Julli [10]

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dude that doesnt maek sense

Explanation:

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3 years ago
Carbon dioxide (CO2) is a gaseous compound. Calculate the percent composition of this compound. Answer using three significant f
Tamiku [17]

Carbon dioxide is a gaseous molecule made up of the elements, C and O. Each mole of carbon dioxide has one mole C and two mole oxygen atoms.

Molar mass of carbon dioxide (CO_{2})=(1 * 12.01\frac{g}{mol}) +(2* 16\frac{g}{mol})=44.01\frac{g}{mol}

Percentage by mass of carbon = \frac{(1*12.01\frac{g}{mol}) }{44.01\frac{g}{mol} } *100=27.3%

Percentage by mass of oxygen = \frac{(2*16\frac{g}{mol})}{44.01\frac{g}{mol} } *100=72.7%

Therefore C is 27.3 % and O is 72.7 % by mass in 1 mol CO_{2}

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4 years ago
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It could be a tide pool but this is pretty vague
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