Hey there!:
H is always +1 so the H's have a +3 charge.
O is always -2 so the O's have a -8 charge .
Now, suppose oxidation state for P = X , then :
+3 + X + (-8) = 0 (because of neutral molecule)
x = 8 - 3
x = + 5
So, X = +5 oxidation state.
Answer C
Hope that helps!
Equation is as follow,
<span> 2 AgNO</span>₃<span> + MgBr</span>₂<span> </span>→ <span>2 AgBr + Mg(NO</span>₃<span>)</span>₂
According to eq.
339.74 g (2 moles) AgNO₃ produces = 375.54 g (2 moles) of AgBr
So,
22.5 g AgNO₃ will produce = X g of AgBr
Solving for X,
X = (22.5 g × 375.54 g) ÷ 339.74 g
X = 24.87 g of AgBr
This is a combustion reaction because it is being combined with oxygen. Then to balance you will put the number of carbons you have or 4 in front of the CO2 and then same with H2. Then you will add up the oxygen and divide it by two to get. 1, (13/2), 4, 5
CₓHₐ + (x+a/4)O₂ = xCO₂ + a/2H₂O
n(CO₂)=4.69 mg/44.01 mg/mmol = 0.1066 mmol
n(H₂O)=1.10 mg/18.02 mg/mmol = 0.06104 mmol
C : H = 0.1066 : 0.06104*2 = 0.1066 : 0.12208 = 1 : 1.1453 = 7 : 8
C₇H₈ + 9O₂ = 7CO₂ + 4H₂O
C₇H₈
