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Harman [31]
3 years ago
15

As a result of recent weather activity, there’s less water available for human consumption. Which biome is affected the most by

this change?
a)tundra
b)taiga
c)saltwater
d)freshwater
Physics
2 answers:
andreev551 [17]3 years ago
7 0
The correct answer for this question is this one: "d)freshwater"
<span>As a result of recent weather activity, there’s less water available for human consumption. The biome that is affected the most by this change is that <u>freshwater</u></span>
Hope this helps answer your question and have a nice day ahead.
Molodets [167]3 years ago
5 0

Answer: d)freshwater

The freshwater biome will be most likely to be affected by the weather conditions as the freshwater reservoirs accumulates water from sources like rain, flood and melting of snow. The reservoirs form are groundwater, river, lakes, ponds and others. In the absence of rain the water will not be accumulated in the biome and will effect the life forms living there.

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A shot is fired at an angle of 60 degree horizontal with Kinetic energy E. If air resistance is ignored, the K.E at the top of t
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I'm going to assume that it means a direction aimed 60 degrees
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Now, I'll answer the question that I have invented.

When the shot is fired with speed of 'S' in that direction,
the horizontal component of its velocity is    S cos(60)  =  0.5 S ,
and the vertical component is   S sin(60) = S√3/2  =  0.866 S .  (rounded)

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-- 0.25 of its kinetic energy is due to its horizontal velocity.
That doesn't change. 

-- So at the top of its trajectory, its KE is 0.25 of what it had originally. 

That's  E/4 .
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The correct answer is 1 and 4.

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a moving billiard ball collides with an identical stationary billiard ball in an elastic collision. after the collision, the sec
MArishka [77]

A billiard ball collides with a stationary identical billiard ball to make it move. If the collision is perfectly elastic, the first ball comes to rest after collision.

<h3>Why does the first ball comes to rest after collision ?</h3>

Let m be the mass of the two identical balls.  

u1 = velocity before the collision of ball 1

u2 = 0 = velocity of second ball that is at rest

v1 and v2 are the velocities of the balls after the collision.

From the conservation of momentum,

∴ mu1 + mu2 = mv1 + mv2

∴ mu1 = mv1 + mv2

∴ u1 = v1 + v2

In an elastic collision, the kinetic energy of the system before and after collision remains same.

\frac{1}{2}  mu_1^2+0=\frac{1}{2}  mv_1^2+\frac{1}{2}  mv_2^2

∴  \frac{1}{2}  m(v_1+v_2 )^2=\frac{1}{2} mv_1^2+\frac{1}{2}mv_2^2

∴ \frac{1}{2} mv_1^2+\frac{1}{2} mv_2^2+mv_1 v_2=\frac{1}{2}  mv_1^2+\frac{1}{2} mv_2^2

∴ mv₁v₂ = 0

  1. It is impossible for the mass to be zero.
  2. Because the second ball moves, velocity v2 cannot be zero.
  3. As a result, the velocity of the first ball, v1, is zero, indicating that it comes to rest after collision.
<h3>What is collision ?</h3>

An elastic collision is a collision between two bodies in which the total kinetic energy of the two bodies remains constant. There is no net transfer of kinetic energy into other forms such as heat, noise, or potential energy in an ideal, fully elastic collision.

Can learn more about elastic collision from brainly.com/question/12644900

#SPJ4

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