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3 years ago

What kind of image does the lens in a camera produce?

Physics

1 answer:

salantis [7]3 years ago

4 0

real and upside down

Explanation:

The lens of a camera produce a real and upside down image. Lens in camera allows for images to form on the film inside a camera.

The image formed is real because it falls on the light sensitive screen where the image forms.
Here the lens converges the light.
On the screen, the image is inverted, this is a sort of reversed image that is rotated 180 degrees.
Images in a lens is usually real and inverted i.e upside down.

Learn more:

lens brainly.com/question/8776909

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Let's say you have two tuning forks which are supposed to produce the same frequency, 512 Hz. One is of good quality, but the ot

solong [7]

Answer:

= 2 beats per seconds

Explanation:

From |f -f'| = modulus of the difference between the frequency given.

f = 510Hz and f' = 512Hz

Difference between the frequency will give us the number of beat per seconds.

i.e 2 beats per seconds

These also shows how to get the period of the tuning forks.

7 0

3 years ago

What is the trend noticed with the inner planets

lutik1710 [3]

The inner planets are closer to the Sun and are smaller and rockier. ... The outer planets are further away, larger and made up mostly of gas. The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus, Earth and Mars.Apr 23, 2014

7 0

3 years ago

g determine what frequency is required of a source powering a 100 uf capacitor a 500 ohm resistor and a s50 mH inductor in serie

polet [3.4K]

Answer: $71.16\ Hz$

Explanation:

Given

Capacitance $C=100\ \mu F$

Resistance $R=500\ \Omega$

Inductance $L=50\ mH$

In LCR circuit, current is maximum at resonance frequency i.e.

$X_L=X_C\ \text{and}\ \omega_o=\dfrac{1}{\sqrt{LC}}$

Insert the values

$\Rightarrow \omega_o=\dfrac{1}{\sqrt{50\times 10^{-3}\times 100\times 10^{-6}}}\\\\\Rightarrow \omega_o=\dfrac{1}{\sqrt{5}\times 10^{-3}}\\\\\Rightarrow \omega_o=0.447\times 10^{3}$

Also, frequency is given by

$\Rightarrow 2\pi f=\omega_o\\\\\Rightarrow f=\frac{\omega_o}{2\pi}$

$\Rightarrow f=\dfrac{1}{2\pi}\times 0.447\times 10^3\\\\\Rightarrow f=71.16\ Hz$

8 0

3 years ago

Scientist do their work by using inquiry. Inquiry is:

lana [24]

Answer:

an act of asking for information.

8 0

3 years ago

Read 2 more answers

Show all work.

lys-0071 [83]

The new gravitation force at the new location is 40 N

Explanation:

The weight of the astronaut is given by the equation

$F=mg$ (1)

where

m is the mass of the astronaut

g is the acceleration of gravity

The acceleration of gravity at a certain distance $r$ from the centre of the Earth is given by

$g=\frac{GM}{r^2}$

where G is the gravitational constant and M is the Earth's mass. So we can rewrite eq.(1) as

$F=\frac{GMm}{r^2}$

When the astronaut is on the Earth's surface, $r=R$ (where R is the Earth's radius), so his weight is

$F=\frac{GMm}{R^2}=640 N$

Later, he moves to another location where his distance from the Earth's surface is 3 times the previous distance, so the new distance from the Earth's centre is

$r'=3R+R=4R$

Therefore, the new weight is

$F'=\frac{GMm}{(4R)^2}=\frac{1}{16}\frac{GMm}{R^2}=\frac{F}{16}$

Which means that his weight has decreased by a factor 16: therefore, the new weight is

$F'=\frac{640}{16}=40 N$

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

3 0

3 years ago