All categories

3 years ago

17.

Physics

1 answer:

DaniilM [7]3 years ago

6 0

Answer:

t = 7 seconds

Explanation:

Given that,

The acceleration of a car, a = 4 m/s²

The initial velocity of the car, u = 0

Final velocity of the car, v = 28 m/s

We need to find how much time the car to reach a speed of 28 m/s. Using the definition of the acceleration of a car. It is given by :

$a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{28}{4}\\\\t=7\ s$

So, it will take 7 seconds to reach a speed of 28 m/s.

You might be interested in

Something that orbiys other things in space

MAXImum [283]

Answer: well we all orbit the sun all the planets do so the

SuN

Explanation: two words common sense

8 0

3 years ago

The driver of a car is driving the car very fast.

PIT_PIT [208]

Because the persons head is probably slammed into some part of the car and that means that the persons slammed on the brakes really hard so the person is probably injured
i hope this helps

6 0

3 years ago

Read 2 more answers

Stella has poured 3 cups of water into a 1-L soda bottle. Stella then sealed the bottle and placed it in the sunlight. What natu

KonstantinChe [14]

Answer is: A. water cycle.
Under influence of sunlight (energy), water evaporates (liquid phase transform into gas phase). Gas, after contact with bottle, turns into liquid phase again (condensation). That is happening with water in nature also (water moves from one reservoir to another).

3 0

3 years ago

Why are watersheds important to humans?

larisa86 [58]

Answer:

The surface water features and storm water runoff within watershed ultimately drain to other bodies of water.

Explanation:

8 0

4 years ago

I have a bottle of gas, the bottle can expand and contract. Initially the gas is at 1 kpa of pressure and a volume of 1 Liter, a

drek231 [11]

Answer:

P₂ = 1.22 kPa

Explanation:

This problem can be solved using the equation of state:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

where,

P₁ = initial pressure = 1 KPa

P₂ = final pressure = ?

V₁ = initial Volume = 1 liter

V₂ = final volume = 1.1 liter

T₁ = initial temperature = 290 k

T₂ = final temperature = 390 k

Therefore,

$\frac{(1\ kPa)(1\ liter)}{290\ k} =\frac{(P_2)(1.1\ liter)}{390\ k}\\\\P_2= \frac{(1\ kPa)(1\ liter)(390\ k)}{(290\ k)(1.1\ liter)}$

P₂ = 1.22 kPa

7 0

3 years ago