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Tema [17]
3 years ago
15

If you write 14 to the 6 power in expanded form, how many factor will there be?

Mathematics
2 answers:
Eddi Din [679]3 years ago
7 0

Answer:

49

Step-by-step explanation:

The expanded form of 14 to the power 6 can be written as follows

14^{6}= 2^{6}\times 7^6

since 2 and 7 are prime numbers hence they can not be broken down into smaller factors.

now according the rule of finding factors

total number of factor= (a+1)*(b+1)

where a and b are powers of the prime factors

therefore, total number of factor= (6+1)*(6+1)= 7*7= 49

shepuryov [24]3 years ago
6 0
14 to the 6th power is 7,529,536. There are zero factors.
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(2x^9y^n) (4x²y^10)-8x^11 y^20                        i say the answer 1 or 10

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

**In one of my You-Tube videos, it talks about all six exponential rules. The video is titled "Six Exponential Rules". Go check it out and get as much assistance as you can from the tutorial.

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