1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tema [17]
3 years ago
15

If you write 14 to the 6 power in expanded form, how many factor will there be?

Mathematics
2 answers:
Eddi Din [679]3 years ago
7 0

Answer:

49

Step-by-step explanation:

The expanded form of 14 to the power 6 can be written as follows

14^{6}= 2^{6}\times 7^6

since 2 and 7 are prime numbers hence they can not be broken down into smaller factors.

now according the rule of finding factors

total number of factor= (a+1)*(b+1)

where a and b are powers of the prime factors

therefore, total number of factor= (6+1)*(6+1)= 7*7= 49

shepuryov [24]3 years ago
6 0
14 to the 6th power is 7,529,536. There are zero factors.
You might be interested in
Work out 3/5 of 900
Mars2501 [29]

Answer:

540

Step-by-step explanation:

1. We assume, that the number 900 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 900 is 100%, so we can write it down as 900=100%.

4. We know, that x is 3.5% of the output value, so we can write it down as x=3.5%.

5. Now we have two simple equations:

1) 900=100%

2) x=3.5%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

900/x=100%/3.5%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 3.5% of 900

900/x=100/3.5

(900/x)*x=(100/3.5)*x       - we multiply both sides of the equation by x

900=28.571428571429*x       - we divide both sides of the equation by (28.571428571429) to get x

900/28.571428571429=x

31.5=x

x=31.5

now we have:

3.5% of 900=31.5

3 0
3 years ago
Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 per 5 minutes of childcare.
TEA [102]

Answer:

$9.00

Step-by-step explanation:

0.75 times 12 equals 9

3 0
3 years ago
Read 2 more answers
Find all values of x such that <img src="https://tex.z-dn.net/?f=%5Csqrt%7B4x%5E2%7D%20-%5Csqrt%7Bx%5E2%7D%3D%206" id="TexFormul
tester [92]
There are two answers.
6 and -6
3 0
3 years ago
Find the quotient 115.338 ÷ 2.82​
MaRussiya [10]

Answer:

The quotient is 40.9

6 0
3 years ago
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 201.9-cm and a standard dev
Nesterboy [21]

Answer:

There is a 0.08% probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 201.9-cm and a standard deviation of 2.1-cm. This means that \mu = 201.9, \sigma = 2.1.

For shipment, 9 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

By the Central Limit Theorem, since we are using the mean of the sample, we have to use the standard deviation of the sample in the Z formula. That is:

s = \frac{\sigma}{\sqrt{n}} = \frac{2.1}{\sqrt{9}} = 0.7

This probability is 1 subtracted by the pvalue of Z when X = 204.1.

Z = \frac{X - \mu}{\sigma}

Z = \frac{204.1 - 201.9}{0.7}

Z = 3.14

Z = 3.14 has a pvalue of 0.9992. This means that there is a 1-0.9992 = 0.0008 = 0.08% probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

3 0
3 years ago
Other questions:
  • Chad casts a shadow that is 14.3 feet long. The straight-line distance from the top of Chad’s head to the end of the shadow crea
    8·2 answers
  • Drove 50 km on 6 L of gasoline. Which proportion would help determine how far she can travel on a full 40 L tank of gasoline?
    13·2 answers
  • How do you factor 2x^2-9x-5?
    14·1 answer
  • Two triangles have a scale factor of 5:7, If the area of the smaller triangle is 225cm squared what is the area of the larger tr
    8·1 answer
  • 22. Solve the system
    5·1 answer
  • 1/3x + 8x^4 - 2/3x^2 - x in standard form
    11·1 answer
  • Please help! It would be very much appreciated!
    12·2 answers
  • Mr. Davis has 15 students in his class. He wants to send 3 of his students to pick up books for the class. How many different co
    6·1 answer
  • HELPP YALL! ILL MARK BRAINIEST!!!
    14·1 answer
  • Solve (sin∅+cos∅/ sin∅-cos∅)=(3/2) for 0⁰&lt;∅&lt;360⁰
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!