What is the percent of N in NH3?

Aside from the reaction proceeding in the test tube, there is a second reaction that occurs when you hold the lit splint inside

tino4ka555 [31]

Answer:

c

Explanation:

4 0

4 years ago

Concentration Calculation: Using your Trial 1 ‘difference in final volumes’ data from procedure II and procedure III, and the kn

Digiron [165]

Subtract the mass of the solute from the whole solution volume.

Molarity, percent by mass, and percent by volume are all ways to represent concentration.

By dividing the number of moles by the number of liters of water utilized in the solution, we can compute the molar concentration. Here, for instance, 1.25 L of water has entirely dissolved the acetic acid. In order to determine the molar concentration, which is 0.1332 M, divide 0.1665 moles by 1.25 L. A titration is a method for figuring out the concentration of an unknown solution by using a solution with known concentration.

Finding the concentration for each sample's absorbance on the standard curve is the first step in calculating the sample concentration based on the standard curve. The next step is to multiply the concentration by the dilution factor for each sample.

Learn more about concentration here brainly.com/question/10703427

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8 0

2 years ago

Given the following two quantities: 0.50 mol of CH4 and 1.0 mol of HCl,

Vinil7 [7]

Answer:

(a) HCl

(b) HCl

(c) HCl

(d) HCl

Explanation:

<em>Given: </em>0.50 mol of CH₄ and 1.0 mol of HCl

Using stoichiometry we can calculate the answers to parts a, b, c, and d.

# of moles × Avogadro's number = # of atoms or molecules

Avogadro's number: 6.02 * 10²³

$\displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{6.02\cdot 10^2^3 \ \text{atoms CH}_4}{1 \ \text{mol CH}_4} = 3.01 \cdot 10^2^3 \ \text{atoms CH}_4$
$\displaystyle 1.0\ \text{mol HCl} \cdot \frac{6.02\cdot 10^2^3 \ \text{atoms HCl}}{1 \ \text{mol HCl}} = 6.02 \cdot 10^2^3 \ \text{atoms HCl}$

HCl has more atoms than CH₄.

This is calculated the same way as Part (a); HCl has more molecules than CH₄.

Molar mass of CH₄ = 16.04 g/mol

Molar mass of HCl = 36.458 g/mol

$\displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{16.04 \ \text{g CH}_4}{1 \ \text{mol CH}_4} = 8.02 \ \text{g CH}_4$
$\displaystyle 1.0\ \text{mol HCl} \cdot \frac{36.458 \ \text{g HCl}}{1 \ \text{mol HCl}} = 36.458 \ \text{g HCl}$

HCl has a greater mass than CH₄.

Assuming STP:

Molar volume of any gas at STP is 22.4 L/mol.

$\displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{22.4 \ \text{L CH}_4}{1 \ \text{mol CH}_4} = 11.2 \ \text{L CH}_4$
$\displaystyle 1.0\ \text{mol HCl} \cdot \frac{22.4 \ \text{L HCl}}{1 \ \text{mol HCl}} = 22.4 \ \text{L HCl}$

HCl has a greater volume than CH₄.

5 0

3 years ago

roundup, an herbicide manufactured by monsanto, has the formula C3H8NO5P. How many moles of molecules are there in a 304.3 g sam

Blizzard [7]

First you find the molar mass of the formula.

3C: 36.03g + 8H:8.08g + N: 14.01g + 5O: 80g + P: 30.97g = 169.09g

Then do the mole ratio (304.3g)x(1mole/169.09g) = 1.800 moles

3 0

3 years ago

Which of the following was a major force of atmospheric oxygen?

ad-work [718]

The answer is B photosynthesis

7 0

3 years ago