Answer:
A) Earth and the other inner planets have higher average surface temperatures than the outer planets.
Explanation:
the earth and the other inner planets have higher average surface temperatures than the outer planets.
The reason for this response is due to the distance between the sun and the respective planet, the source of energy generation is the sun and the only way in which the temperature increase of each planet is guaranteed is by radiation, the further away a planet is from its star, its temperature will decrease. Although it is also important to highlight the atmospheric composition of the planet if this planet in its stratosphere has high density clouds that do not allow the entry of solar radiation, the temperature of the planet's surface will not increase, independent of the distance from the sun, but these are more complex cases where specialists in that area enter to perform a study in detail.
Answer: 0.25 m/s
Explanation: Speed = wavelengt · frequency
v = λf and frequency is 1/period f = 1/T
Then v = λ/T = 5 m / 20 s = 0.25 m/s
Answer:
Going with the current. You every watch Finding Nemo and the turtle guy says " Going with the waves bro"
Explanation:
Answer:
Wavelength of the sound wave that reaches your ear is 1.15 m
Explanation:
The speed of the wave in string is
![v=\sqrt{\frac{T}{\mu} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7BT%7D%7B%5Cmu%7D%20%7D)
where T= 200 N is tension in the string ,
=1.0 g/m is the linear mass density
![v=\sqrt{\frac{200}{1\times 10^{-3} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B200%7D%7B1%5Ctimes%2010%5E%7B-3%7D%20%7D)
![v=447.2 m/s](https://tex.z-dn.net/?f=v%3D447.2%20m%2Fs)
Wavelength of the wave in the string is
![\lambda =2L=2\times 0.8=1.6 m](https://tex.z-dn.net/?f=%5Clambda%20%3D2L%3D2%5Ctimes%200.8%3D1.6%20m)
The frequency is
![f=\frac{v}{\lambda} \\f=\frac{447.2}{1.6}\\f=298.25 Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bv%7D%7B%5Clambda%7D%20%5C%5Cf%3D%5Cfrac%7B447.2%7D%7B1.6%7D%5C%5Cf%3D298.25%20Hz)
The required wavelength pf the sound wave that reaches the ear is( take velocity of air v=344 m/s)
![\lambda=\frac{v_{air}}{f} \\\lambda=\frac{344}{298.25} \\\lambda=1.15 m](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bv_%7Bair%7D%7D%7Bf%7D%20%5C%5C%5Clambda%3D%5Cfrac%7B344%7D%7B298.25%7D%20%5C%5C%5Clambda%3D1.15%20m)