Answer:
The extension of the spring is 0.392 m.
Explanation:
Given;
spring constant, k = 50 N/m
mass attached to the spring, m = 2.0 kg
let the extension of the spring = x
The extension of the spring is calculated by applying Hook's law;
F = kx
mg = kx

Therefore, the extension of the spring is 0.392 m.
This is an example of Uniform Speed
EXPLANATION
Uniform Speed => no change in speed
Uniform Accelerations Speed => There is a change in speed, but the acceleration remains the same.
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10,000 units of momentum.
p=mv
20,000=m(2v)
10,000=mv
Answer:
λ = 5.656 x 10⁻⁷ m = 565.6 nm
Explanation:
Using the formula of fringe spacing from the Young's Double Slit experiment, which is given as follows:

where,
λ = wavelength = ?
Δx = fringe spacing = 1.6 cm = 0.016 m
L = Distance between slits and screen = 4.95 m
d = slit separation = 0.175 mm = 0.000175 m
Therefore,

<u>λ = 5.656 x 10⁻⁷ m = 565.6 nm</u>