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erma4kov [3.2K]

3 years ago

6

Sean, an astronaut stands on the edge of a lunar crater and throws a Frisbeeâ„˘ horizontally with a velocity of 5.00 m/s. With n

o atmosphere on the moon the Frisbee â„˘ will not have any force of lift so it will â€śflyâ€ť like a stone. The floor of the crater is 77.0 m below the astronaut. What horizontal distance will the Frisbeeâ„˘ travel before hitting the floor of the crater? (The acceleration of gravity on the moon is 1/6th that of the Earth).

1 answer:

motikmotik3 years ago

4 0

Answer:

48.55mm

Explanation:

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An electron passes through a point 2.83 cm 2.83 cm from a long straight wire as it moves at 35.5 % 35.5% of the speed of light p

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Answer:

The magnitude of electron acceleration is $2.34 \times 10^{15}$ $\frac{m}{s^{2} }$

Explanation:

Given:

Distance from the wire to the field point $r = 2.83 \times 10^{-2}$ m

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First find the magnetic field due to wire,

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Where $\mu_{o} = 4\pi \times 10^{-7}$

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$F = qvB$

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$F = 21.3 \times 10^{-16}$ N

From the newton's second law

$F = ma$

Where $m =$ mass of electron $= 9.1 \times 10^{-31}$ kg

So acceleration is given by,

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Therefore, the magnitude of electron acceleration is $2.34 \times 10^{15}$ $\frac{m}{s^{2} }$

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What is one way to increase the amplitude of a wave in a medium?

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m is the mass of the object

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We see from the formula that the force of gravity acting on an object depends on the mass: the larger the mass of the object, the stronger the gravitational force acting on it, and the smaller the mass, the weaker the force of gravity.

The factor that does not change is the acceleration of gravity, which is constant ( $9.8 m/s^2$ ) if we are near the Earth's surface, and implies that all the objects in free fall accelerate at the same rate towards the ground, regardless of their size and weight.

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