Answer:
The increase in potential energy of the ball is 115.82 J
Explanation:
Conceptual analysis
Potential Energy (U) is the energy of a body located at a certain height (h) above the ground and is calculated as follows:
U = m × g × h
U: Potential Energy in Joules (J)
m: mass in kg
g: acceleration due to gravity in m/s²
h: height in m
Equivalences
1 kg = 1000 g
1 ft = 0.3048 m
1 N = 1 (kg×m)/s²
1 J = N × m
Known data
![h_2 = 265ft * \frac{0.3048m}{ft} = 80.77m](https://tex.z-dn.net/?f=h_2%20%3D%20265ft%20%2A%20%5Cfrac%7B0.3048m%7D%7Bft%7D%20%3D%2080.77m)
![h_1 = 3ft * \frac{0.3048m}{ft} = 0.914m](https://tex.z-dn.net/?f=h_1%20%3D%203ft%20%2A%20%5Cfrac%7B0.3048m%7D%7Bft%7D%20%3D%200.914m)
![m = 148g*\frac{1kg}{1000g} = 0.148kg](https://tex.z-dn.net/?f=m%20%3D%20148g%2A%5Cfrac%7B1kg%7D%7B1000g%7D%20%3D%200.148kg)
![g = 9.8 \frac{m}{s^2}](https://tex.z-dn.net/?f=g%20%3D%209.8%20%5Cfrac%7Bm%7D%7Bs%5E2%7D)
Problem development
ΔU: Potential energy change
ΔU = U₂ - U₁
U₂ - U₁ = mₓgₓh₂ - mₓgₓh₁
U₂ - U₁ = mₓg(h₂ - h₁)
![U_2 - U_1 = 0.148kg * 9.8 \frac{m}{s^2}*(80.77m - 0.914m) = 115.82 N * m = 115.82J](https://tex.z-dn.net/?f=U_2%20-%20U_1%20%3D%200.148kg%20%2A%209.8%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%2A%2880.77m%20-%200.914m%29%20%3D%20115.82%20N%20%2A%20m%20%3D%20115.82J)
The increase in potential energy of the ball is 115.82 J
Answer:
R=2F
Explanation:
As the forces are in same direction so the resultant force will be:
R=F+F
R=2F
Answer:
a.) L = 2.64 kgm^2/s
b.) V = 4.4 m/s
Explanation: Jessica stretches her arms out 0.60 m from the center of her body. This will be considered as radius.
So,
Radius r = 0.6 m
Mass M = 2 kg
Velocity V = 1.1 m/s
Angular momentum L can be expressed as;
L = MVr
Substitute all the parameters into the formula
L = 2 × 1.1 × 0.6 = 1.32kgm^2s^-1
the combined angular momentum of the masses will be 2 × 1.32 = 2.64 kgm^2s-1
b. If she pulls her arms into 0.15 m,
New radius = 0.15 m
Using the same formula again
L = 2( MVr)
2.64 = 2( 2 × V × 0.15 )
1.32 = 0.3 V
V = 1.32/0.3
V = 4.4 m/s
Her new linear speed will be 4.4 m/s
Kinetic friction (also referred to as dynamic friction) is the force that resists the relative movement of the surfaces once they're in motion.
https://www.khanacademy.org › stat...
Static and kinetic friction example (video) | Khan Academy
Answer a would be static friction
Answer b is fluid friction
(Air resistance is fluid friction. Fluid friction is the friction experienced by objects which are moving in a fluid and the air is a fluid.)
Answer c is static friction
ANSWER D IS KINETIC FRICTION
Hope this helps :D
Cold freshwater<span> is </span>denser<span> than </span>warm seawater<span>, because of the salinity and temperature variations. Cold water would have less salt since the solubility of the salt is lower as compared to warm water. Hope this answers the question. Have a nice day.</span>