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Anuta_ua [19.1K]
2 years ago
5

Determine the orbits period of the moon when the distance between the earth and the moon is 3.82 x 10 to the power of 8

Physics
2 answers:
777dan777 [17]2 years ago
6 0

Answer:

3820000000

Explanation:

Gennadij [26K]2 years ago
3 0
This statement is infact true
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A 11.0 kg satellite has a circular orbit with a period of 1.80 h and a radius of 7.50 × 106 m around a planet of unknown mass. I
Anuta_ua [19.1K]

Answer:

Explanation:

Expression for times period of a satellite can be given as follows

Time period T = 1.8 x 60 x 60

= 6480

T² = \frac{4\times \pi^2\times r^3}{GM} where T is time period , r is radius of orbit , G is gravitational constant and M is mass of the satellite.

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GM = 4 x 3.14² x 7.5³ x 10¹⁸ / 6480²

= 3.96 X 10¹⁴

Expression for acceleration due to gravity

g = GM / R² where R is radius of satellite

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R² = 3.96 X 10¹⁴ / 20

= 1.98 x 10¹³ m

R= 4.45 x 10⁶ m

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A force of 210 N is applied to an object and the object accelerates at 14m/s2. Determine the mass of the object in kg.
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