The answer is Carbon. Beyond being the only element listed here that is located in the second row, it is also in the fourteenth column of the table if you count from left to right. Hope this helps!
The question here would be what is the volume of the room. The density of air that is given has no use. We simply multiply the dimensions given of the room to determine the volume.
<span>43.0m × 18.0m × 15.0m = 11610m^3 ( 3.28 ft / 1 m)^3 = 4.09 x 10^5 ft^3</span>
To solve the problem it is necessary to apply the concepts related to Byle's Law and Avogadro's Law.
The ideal gas equation would help us find the final solution to the problem, defined by
Where,
T= Temperature of the gas
R = Universal as constant
n = number of moles
V = Volume
P = Pressure
For our case we have that the mass of Zn is 2.2g in moles would be
![[tex]Zn = \frac{2.2}{65}](https://tex.z-dn.net/?f=%5Btex%5DZn%20%3D%20%5Cfrac%7B2.2%7D%7B65%7D)
[/tex]
We know that 1 mole of hydrogen gas is proceed by 1 mole of zinc and the result is 
, then Hydrogen can produce the same quantity,
Applying the previous equation we have that
Therefore the volume of hydrogen gas is collected is 0.829L
Long straight distance that a person can swim is 5.64 m.
<h3>What is the
Long straight distance?</h3>
The line that runs form one end of the circle to another is called the diameter of the circle. The pool is a circle according to the question and the long straight distance that a person can swim is the same of the diameter of the circular pool.
Now we have;
A = πr^2
A = area of pool
r = radius of pool
r = √A/ π
r = √25/3.142
r = 2.82m
Diameter of the circular pool = 2 r = 2 (2.82 cm) = 5.64 m
Learn more about circle: brainly.com/question/11833983
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Missing parts;
An ad for an above-ground pool states that it is 25 m2. From the ad, you can tell that the pool is a circle. If you swim from one point at the edge of the pool to another, along a straight line, what is the longest distance d you can swim? Express your answer in three significant figures.
Answer:
0.0241875 m
Explanation:
= Mass of quarterback = 80 kg
= Mass of football = 0.43 kg
= Velocity of quarterback
= Velocity of football = 15 m/s
Time taken = 0.3 seconds
In this system as the linear momentum is conserved
Assuming this velocity is constant
The distance the quarterback will move in the horizontal direction is 0.0241875 m
