The escape velocity of a rocket from the earth is 11kms^-1. Taking the acceleration due to gravity as 9.8ms^-2, calculate the ra
1 answer:
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Answer:
Explanation:
As we know that in AC circuit we have
here we have
V = 59 V
i = 5.05 A
so we will have
also we know that
here we will have
Answer:
v_{ average} = 5.57
Explanation:
The most probable value of a measure is
v_average = ∑ x_i
where N is the number of measurements
in tes case N = 3
v_{average} = ⅓ (5.63 +5.54 + 5.53)
V_{average} = 5,567
The number of significant figures must be equal to the number of figures that have the least in the readings.
v_{ average} = 5.57