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Marysya12 [62]
3 years ago
10

Ashley is flying a plane that has to reach a gradient of 360m/km in order to take off and not crash. Her goal is to travel from

sea level to an elevation of 1000m at a distance of 2.8km. Calculate the gradient of Ashley’s flight and determine if she will crash!

Physics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

She is likely to crash because her flight gradient is lesser than the flight gradient required gradient to avoid crashing

Explanation:

The given parameters are;

The required gradient of the plane Ashley is flying needs to reach in order to take off and not crash = 360 m/km

The initial elevation of the plane Ashley is flying = Sea level = 0 m

The goal Ashley intends to make = Elevation of 1000 m at 2.8 km. distance

∴ Ashley's goal = Traveling from sea level to 1000 m at 2.8 km horizontal distance

We have;

The gradient  = Rate of change of elevation/(Horizontal distance)

Therefore;

The gradient of Ashley's flight = (1000 - 0)/(2.8 - 0) = 357.143 m/km

The gradient of Ashley's flight ≈ 357.143 m/km which is lesser than the required 360 m/km in order to take off and not crash, therefore, she will crash.

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A machine accelerates a 5 kg missile from rest to a speed of 5 km/s. The net force accelerating the missile 500,000 N. How long
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2 years ago
One event occurs at the origin at t equal to zero, and a second events occurs at the point x=5m along the x-axis at time with ct
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Answer:

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Explanation:

We can define the separation between two events (using the + - - - signature)  as :

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where the separation will be lightlike if is equal to zero, timelike if is positive and spacelike if is negative.

For our problem

c t_1 = 0

x_1 = 0

ct_2 = 4 \ m

x_2 = 5 \ m

(\Delta s )^2  = (4 \ m - 0 )^2 - ( 5 \ m - 0)^2

(\Delta s )^2  = (4 \ m )^2 - ( 5 \ m 0)^2

(\Delta s )^2  = 16 \ m^ 2 - 25 \ m^2

(\Delta s )^2  = - 9\ m^2

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The runner has initial velocity vector

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and acceleration vector

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8 0
3 years ago
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