•Every action has an equal and opposite reaction (the object is putting force on the target, and the target is putting an equal amount of force back)
•Am object in motion (the object) will stay in motion unless an outside force acts upon it (the Target)
And as for the third one I really don’t know, those seem to be the only two, I’m sorry. I did what a could, Hope it kinda helps :)
Answer:
The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N
(b) the force the light beam exerts is much too small to be felt by the man.
Explanation:
Given;
cross-sectional area of the man, A = 0.500m²
intensity of light, I = 35.5kW/m²
If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;
P = I/c
where;
P is the pressure of the incident light
I is the intensity of the incident light
c is the speed of light

F = PA
where;
F is the force of the incident light on the man
P is the pressure of the incident light on the man
A is the cross-sectional area of the man
F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N
The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N
Therefore, the force the light beam exerts is much too small to be felt by the man.
Answer:
Explanation:
According to Newton's law of Gravitation, the force
exerted between two bodies of masses
and
and separated by a distance
is equal to the product of their masses and inversely proportional to the square of the distance:
(1)
Where:
is the Gravitational Constant and its value is
is the mass of the Sun
is the mass of the Earth
is the distance between the Sun and the Earth
Substituting the values in (1):
(2)
Finally:
This is the gravitational force acting on the earth due to the sun
<u><em>The question doesn't provide enough data to be solved, but I'm assuming some magnitudes to help you to solve your own problem</em></u>
Answer:
<em>The maximum height is 0.10 meters</em>
Explanation:
<u>Energy Transformation</u>
It's referred to as the change of one energy from one form to another or others. If we compress a spring and then release it with an object being launched on top of it, all the spring (elastic) potential energy is transformed into kinetic and gravitational energies. When the object stops in the air, all the initial energy is now gravitational potential energy.
If a spring of constant K is compressed a distance x, its potential energy is

When the launched object (mass m) reaches its max height h, all that energy is now gravitational, which is computed as

We have then,


Solving for h

We have little data to work on the problem, so we'll assume some values to answer the question and help to solve the problem at hand
Let's say: x=0.2 m (given), K=100 N/m, m=2 kg
Computing the maximum height


The maximum height is 0.10 meters