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evablogger [386]
3 years ago
8

Find the value of X to the nearest tenth. Thank you!!!

Mathematics
1 answer:
Greeley [361]3 years ago
5 0

Answer:

84.5

Step-by-step explanation:

Use trig functions to find x. Trig functions are special relationships which exits between the sides of right triangles. Since you need to find x the hypotenuse and you have the adjacent side to 77 degree angle use cosine.

Cos 77 = 19/x

0.22495 = 19/x

19/0.22495 = x

84.5 = x


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Please help!!!!!!!!!!!!!!!
Andreas93 [3]

Answer:

a)  12/91

b) about 67 times;  (66 2/3)

Step-by-step explanation:

a) total of frequencies is 90 and frequency for a 3 is 11

however, the question said if the dice is rolled once more, then that raises the 11 to 12 and the frequency total from 90 to 91

let 'x' = # of sixes rolled out of 500 times

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7 0
3 years ago
2x + 22 = 4(x + 3)<br> Please help me
Annette [7]

Answer: x=5

Step-by-step explanation:

2x+22=4(x+3)

First distribute

2x+22=4x+12

Now intractable 2x from both sides

22=2x+12

Now subtract 12 from both sides

10=2x

Now divide by 2 to get x alone

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So

x=5

4 0
2 years ago
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Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
3 years ago
~PLEASE HELP ASAP OFFERING 10 POINTS~
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T = c + cb
t - c = cb
(t - c)/c = b
b = (t - c)/c
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