Answer:
200 grams of sodium hydroxide produce 595 grams of sodium sulfate if we have an excess of sulphuric acid
Explanation:
2 NaOH + H2SO4 → 2 H20 + Na S04
From the above chemical equation we can state that
2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid to produce 1 mole of sodium sulfate.
Now if we start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid then the amount in grams of sodium sulfate will be formed
2 moles of sodium hydroxide produce 1 mole of sodium sulfate.
In term of mass, we can say that
40 grams of sodium hydroxide produce 119grams of sodium sulfate
1 grams of sodium hydroxide produce (119/40) grams of sodium sulfate
then 200 grams of sodium hydroxide produce ((119*200)/40) grams of sodium sulfate
or 200 grams of sodium hydroxide produce 595 grams of sodium sulfate
increases in solution resulting removal of
by forming
. Hence, according to Le-chatelier principle, equilibrium will shift towards right. So more
will dissolve
is added then concentration of
increases in solution resulting shifting of equilibrium towards left in accordance with Le-chatelier principle. So less