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3 years ago

2 NaOH + H2SO4 → 2 H,0 + Na S04

Chemistry

1 answer:

maw [93]3 years ago

6 0

Answer:

200 grams of sodium hydroxide produce 595 grams of sodium sulfate if we have an excess of sulphuric acid

Explanation:

2 NaOH + H2SO4 → 2 H20 + Na S04

From the above chemical equation we can state that

2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid to produce 1 mole of sodium sulfate.

Now if we start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid then the amount in grams of sodium sulfate will be formed

2 moles of sodium hydroxide produce 1 mole of sodium sulfate.

In term of mass, we can say that

40 grams of sodium hydroxide produce 119grams of sodium sulfate

1 grams of sodium hydroxide produce (119/40) grams of sodium sulfate

then 200 grams of sodium hydroxide produce ((119*200)/40) grams of sodium sulfate

or 200 grams of sodium hydroxide produce 595 grams of sodium sulfate

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Read 2 more answers

A disk of radius 2.0 cm has a surface charge density of 6.3 μC/m2 on its upper face. What is the magnitude of the electric field

maksim [4K]

Answer:

the electric field at Z = 12 cm is E = 9.68 × 10³ N/C = 9.68 kN/C

Explanation:

Given: radius of disk, R = 2.0 cm = 2 × 10⁻² cm, surface charge density,σ = 6.3 μC/m² = 6.3 × 10⁻⁶ C/m², distance on central axis, z = 12 cm = 12 × 10⁻² cm.

The electric field, E at a point on the central axis of a charged disk is given by E = σ/ε₀( $1 - \frac{z}{\sqrt{z^{2} + R^{2} } }$ )

Substituting the values into the equation, it becomes

E = σ/ε₀( $1 - \frac{z}{\sqrt{z^{2} + R^{2} } }$ ) = 6.3 × 10⁻⁶/8.854 × 10⁻¹²( $1 - \frac{0.12}{\sqrt{0.12^{2} + 0.02^{2} } }$ ) = 7.12 × 10⁵( $1 - \frac{0.12}{0.1216}$ ) = 7.12 × 10⁵(1 - 0.9864) = 7.12 × 10⁵ × 0.0136 = 0.0968 × 10⁵ = 9.68 × 10³ N/C = 9.68 kN/C

Therefore, the electric field at Z = 12 cm is E = 9.68 × 10³ N/C = 9.68 kN/C

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3 years ago