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Nimfa-mama [501]
4 years ago
14

2 NaOH + H2SO4 → 2 H,0 + Na S04

Chemistry
1 answer:
maw [93]4 years ago
6 0

Answer:

200 grams of sodium  hydroxide produce 595 grams of sodium sulfate if we have an excess of sulphuric acid

Explanation:

2 NaOH + H2SO4 → 2 H20 + Na S04

From the above chemical equation we can state that

2 moles of sodium  hydroxide reacts with 1 mole of  sulfuric acid to produce 1 mole of sodium sulfate.

Now if we  start with 200 grams of sodium  hydroxide and you have an excess of sulfuric acid then the amount in grams of sodium sulfate will be formed

2 moles of sodium  hydroxide produce 1 mole of sodium sulfate.

In term of mass, we can say that

40 grams of sodium  hydroxide produce 119grams of sodium sulfate

1 grams of sodium  hydroxide produce (119/40) grams of sodium sulfate

then 200 grams of sodium  hydroxide produce ((119*200)/40) grams of sodium sulfate

or 200 grams of sodium  hydroxide produce 595 grams of sodium sulfate

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The smell of dirty gym socks is caused by the compound caproic acid(contains H, C, O). Combustion of 0.844 g of caproic acid pro
adoni [48]

<u>Answer:</u> The molecular formula for the given organic compound is C_2H_{32}O_4

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.784g

Mass of H_2O=1.92g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.784 g of carbon dioxide, \frac{12}{44}\times 0.784=0.214g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.92 g of water, \frac{2}{18}\times 1.92=0.213g of hydrogen will be contained.

Mass of oxygen in the compound = (0.844) - (0.214 + 0.213) = 0.417 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = \frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.214g}{12g/mole}=0.0134moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.213g}{1g/mole}=0.213moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.417g}{16g/mole}=0.0261moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0134 moles.

For Carbon = \frac{0.0134}{0.0134}=1

For Hydrogen = \frac{0.213}{0.0134}=15.89\approx 16

For Oxygen = \frac{0.0261}{0.0134}=1.95\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 16 : 2

The empirical formula for the given compound is CH_{16}O_2

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 116.2 g/mol

Mass of empirical formula = 60 g/mol

Putting values in above equation, we get:

n=\frac{116.2g/mol}{60g/mol}=1.94\approx 2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 2)}H_{(16\times 2)}O_{(2\times 2)}=C_2H_{32}O_4

Hence, the molecular formula for the given organic compound is C_2H_{32}O_4

5 0
3 years ago
Which of the following ideas did Greek philosopher Democritus contribute to the atomic theory?
lozanna [386]

Answer:

c. all matter is composed of small particles,which combine to make larger objects

7 0
3 years ago
Which element is located in group 2 period 2 on the periodic Table?
AnnZ [28]

Answer:

Berilium is located in period 2 group2

Explanation:

you are welcome

4 0
3 years ago
Read 2 more answers
How many molecules of H2O are there in 1.0 g of H2O?
NISA [10]
Molar mass H₂O = 18.0 g/mol

number of moles :

1.0 / 18.0 => 0.055 moles

1 mole -------------- 6.02 x 10²³ molecules
0.055 moles --------  ? molecules

molecules = 0.055 x ( 6.02 x 10²³) / 1

molecules = 3.311x10²² / 1

= 3.311 x 10²² molecules

hope this helps!
8 0
3 years ago
An outdoor grill has a propane (C3H8) tank that holds 4.8 L of gas at a pressure of 5.5 atm. If all of the gas is transferred in
shtirl [24]

Answer: 0.176 atm

Explanation: Solution attached:

Use Boyle's Law to find the new pressure of the gas.

P1V1 = P2V2

Derive for P2

P2 = P1V1 / V2

= 5.5 atm ( 4.8 L ) / 150 L

= 0.176 atm

4 0
3 years ago
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