All categories

3 years ago

2 NaOH + H2SO4 → 2 H,0 + Na S04

Chemistry

1 answer:

maw [93]3 years ago

6 0

Answer:

200 grams of sodium hydroxide produce 595 grams of sodium sulfate if we have an excess of sulphuric acid

Explanation:

2 NaOH + H2SO4 → 2 H20 + Na S04

From the above chemical equation we can state that

2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid to produce 1 mole of sodium sulfate.

Now if we start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid then the amount in grams of sodium sulfate will be formed

2 moles of sodium hydroxide produce 1 mole of sodium sulfate.

In term of mass, we can say that

40 grams of sodium hydroxide produce 119grams of sodium sulfate

1 grams of sodium hydroxide produce (119/40) grams of sodium sulfate

then 200 grams of sodium hydroxide produce ((119*200)/40) grams of sodium sulfate

or 200 grams of sodium hydroxide produce 595 grams of sodium sulfate

You might be interested in

One beaker contains 100 mL of pure water and second beaker contains 100 mL of seawater. The two beakers are left side by side on

gayaneshka [121]

Explanation:

When we add a non-volatile solute in a solvent then due to the impurity added to the solution there will occur an increase in the boiling point of the solution.

This increase in boiling point will be known as elevation in boiling point.

As one beaker contains seawater (water having NaCl) will have some impurity in it. So, more temperature is required by seawater to escape into the atmosphere.

Whereas another beaker has only pure water so it is able to easily escape into the atmosphere since, it contains no impurity.

Thus, we can conclude that level of pure water will decrease more due to non-volatile solute present in it as compared to seawater.

7 0

3 years ago

In the reaction 2CO (g) + O2 (g) 2CO2 (g), how many moles of oxygen gas are needed to react with 24 moles of carbon monoxide

Anuta_ua [19.1K]

12 moles of oxygen gas are needed to react with 24 moles of carbon monoxide.

<u>Explanation:</u>

The molar ratio of carbon monoxide to oxygen 2:1

Which means 2 moles of carbon monoxide is reacting with 1 mole of oxygen.

to produce 2 moles of carbon dioxide.

Therefore, from the molar ratio, we get that 12 moles of oxygen are required to react with 24 moles 0f carbon monoxide.

Molar ratio:

The molar ratio gives the moles of product that are formed from a certain amount of reactant, and also the number of moles of a reactant needed to react with another reactant.

4 0

3 years ago

Answer quickly plzzzz 100 points

Paladinen [302]

Answer:

hydrogen and oxygen

Explanation:

6 0

3 years ago

Read 2 more answers

HELP ME PLEASEEEEE!!!!!!!!!!

AlladinOne [14]

Answer:

I dont know what the answer is

Explanation:

3 0

2 years ago

Read 2 more answers

You wish to make a 0.289 M hydroiodic acid solution from a stock solution of 3.00 M hydroiodic acid. How much concentrated acid

nataly862011 [7]

Answer:

$V_1=9.63mL$

Explanation:

Hello,

In this case, we work on a dilution process in which we can state that the moles remain the same after the dilution process. In such a way, we can write:

$n_1=n_2\\$

That in terms of molarities and volumes is:

$M_1V_1=M_2V_2$

Whereas $M_1$ is the initial molarity (3.00 M) of the stock solution, $M_2$ the molarity of the diluted solution (0.289 M), $V_1$ the aliquot of the stock (concentrated) solution and $V_2$ the volume of the diluted solution (100 mL), thus, we compute $V_1$ as required:

$V_1=\frac{M_2V_2}{M_1} =\frac{0.289M*100mL}{3.00M} \\\\V_1=9.63mL$

Best regards.

7 0

3 years ago