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mel-nik [20]
4 years ago
8

Shay reacts solid zinc and aqueous copper sulfate to form aqueous zinc sulfate and solid copper. If he reacts 10.1 grams of zinc

with 18.6 grams of copper sulfate and yields 20 grams of zinc sulfate and 8.7 grams of copper, then was mass conserved? explain how you know.
Physics
1 answer:
zhenek [66]4 years ago
7 0

Answer:

Now since mass of reactant is equal to mass of the product after the reaction so we can say that mass conservation is applicable here

Explanation:

As we know that zinc reacts with copper sulfate

so the reaction is given as

Zn + CuSO_4 --> ZnSO_4 + Cu

so here we have

Zn = 10.1 g

CuSO_4 = 18.6 g

ZnSO_4 = 20 g

Cu = 8.7 g

Now total mass of reactant is given as

M_1 = 10.1 + 18.6 = 28.7 g

Mass of the product is given as

M_2 = 20 + 8.7 = 28.7 g

Now since mass of reactant is equal to mass of the product after the reaction so we can say that mass conservation is applicable here

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Answer:

Rectangular path

Solution:

As per the question:

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In order to minimize the cost let us denote the side of the square bottom be 'a'

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The cost is:

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Volume of the box, V = a^{2}h = 4^{2}\times 2 = 128            (1)

Total cost, C_{t} = 2a^{2} + 2ah            (2)

From eqn (1):

h = \frac{128}{a^{2}}

Using the above value in eqn (1):

C(a) = 2a^{2} + 2a\frac{128}{a^{2}} = 2a^{2} + \frac{256}{a}

C(a) = 2a^{2} + \frac{256}{a}

Differentiating the above eqn w.r.t 'a':

C'(a) = 4a - \frac{256}{a^{2}} = \frac{4a^{3} - 256}{a^{2}}

For the required solution equating the above eqn to zero:

\frac{4a^{3} - 256}{a^{2}} = 0

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4 years ago
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3 years ago
The total mass of the train and its passengers is 750000kg. The train is traveling at a speed of 84m/s. The driver applies the b
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Answer:

|F| = 393750  N

Explanation:

Given that,

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We need to find the net force acting on the train. The formula for force is given by :

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Answer:

c

Explanation:

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