Answer:
ax = -3.29[m/s²]
ay = -1.9[m/s²]
Explanation:
We must remember that acceleration is a vector and therefore has magnitude and direction.
In this case, it is accelerating downwards, therefore for a greater understanding we will make a diagram of said vector, this diagram is attached.
![a_{x}=-3.8*cos(30) = -3.29 [m/s^{2}]\\ a_{y}=-3.8*sin(30) = -1.9 [m/s^{2}]](https://tex.z-dn.net/?f=a_%7Bx%7D%3D-3.8%2Acos%2830%29%20%3D%20-3.29%20%5Bm%2Fs%5E%7B2%7D%5D%5C%5C%20a_%7By%7D%3D-3.8%2Asin%2830%29%20%3D%20-1.9%20%5Bm%2Fs%5E%7B2%7D%5D)
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A=m/s^2(meter per second square)
Work=joule
Radial acceleration is a=v^2/r. For circular motion, the tangential velocity is v=2pi*r*f.
f is in Hz so 49/60=0.81667Hz.
radius in meters is 0.38m
So a=(2pi*f)^2*r = 10m/s^2
Answer:
it is accepted all over the world
it is more reliable than other kinds of measuring system