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alexandr402 [8]
4 years ago
15

Explain the results of Rutherford’s gold foil experiment and how they changed our model of the atom.

Physics
1 answer:
lianna [129]4 years ago
3 0

Answer:

Explained

Explanation:

Through Rutherford's gold foil experiment, he disproved J.J Thompson's theory. Rutherford was very interested in studying the behavior of x-rays, which was then recently discovered by Curie. When he shot a beam of alpha particles (particles with 2 neutrons and 2 protons, or the Helium atom) toward the gold foil, the particles were deflected by a slight angle. He then theorized that these deflections were due to the existence of a dense nucleus inside the atom. 

Following Rutherford's discovery of the nucleus, Niels Bohr theorized the planetary model of the atomic structure. According to him, the atom is like a solar system wherein the Sun is the nucleus and the planets are the electrons orbiting around it. The electrons and protons move this way because they are influenced by an electric force due to the difference of their charges.

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4 years ago
An unknown charged particle passes without deflection through crossed electric and magnetic fields of strengths 187,500 V/m and
Kobotan [32]

Answer:

Explanation:

Given that

The electric fields of strengths E = 187,500 V/m and

and The magnetic  fields of strengths B = 0.1250 T

The diameter d is 25.05 cm which is converted to 0.2505m

The radius is (d/2)

= 0.2505m / 2 = 0.12525m

The given formula to find the magnetic force is F_{ma}=BqV---(i)

The given formula to find the electric force is F_{el}=qE---(ii)

The velocity of electric field and magnetic field is said to be perpendicular

Electric field is equal to magnectic field

Equate equation (i) and equation (ii)

Bqv=qE\\\\v=\frac{E}{B}

v=\frac{187500}{0.125} \\\\v=15\times10^5m/s

It is said that the particles moves in semi circle, so we are going to consider using centripetal force

F_{ce}=\frac{mv^2}{r}---(iii)

magnectic field is equal to centripetal force

Lets equate equation (i) and (iii)

Bqr=\frac{mv^2}{r} \\\\\frac{q}{m}=\frac{v}{Br}  \\\\\frac{q}{m} =\frac{15\times 10^5}{0.125\times0.12525} \\\\=\frac{15\times10^5}{0.015656} \\\\=95808383.23\\\\=958.1\times10^5C/kg

Therefore,  the particle's charge-to-mass ratio is 958.1\times10^5C/kg

b)

To identify the particle

Then 1/ 958.1 × 10⁵ C/kg

The charge to mass ratio is very close to that of a proton, which is about 1*10^8 C/kg

Therefore the particle is proton.

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Explanation:

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Light waves have some similarities with water and sound waves, but they are not exactly the same. Describe all the differences y
makkiz [27]

<u>Answer:</u>


<h2>All the waves are pertubations that propagate (transport) energy.</h2><h2></h2>

Nevertheless, they have some differences:


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6. <u>Water waves</u> are 2-dimensional waves, while the <u>light and the sound</u> are tridimensional spherical waves

7. Light waves <u>transports energy in the form of </u><u>radiation</u>, while mechanical waves t<u>ransport energy with </u><u>material</u>


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