1.Nuclear charge decreases as the atomic number increases.Immersive Reader
Answer - True
2.In alkali metals, the atomic radius of potassium is greater than
Answer - Lithium
3.While moving across the periodic table from left to right there is an increase in atomic radius.
Answer - False
4.When moving from gold to lead, the atomic radius increases.
Answer - True
5.The picometer is the unit used to measure atomic radii.
Answer - True
6.Which of the following is larger in atomic size?
Answer - Boron
7.Chlorine has a larger atomic radius than fluorine.
Answer - True
8.Atomic size increases across a period.
Answer - False
9.The atomic radius of a nitrogen atom is 70 pm. What is the distance between the nuclei of two bonded nitrogen atoms in a N2 molecule
Answer - 140 pm
10.Arrange the following atoms in order of decreasing atomic radius:
Ga, As, Sn, Sb, Te
Answer - a. Sn, Sb, Te, Ga, As
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Answer:
They are synthesized from raw materials
Explanation:
All synthesized products goes through lots of processes. This processes involves the conversion of substances known as raw materials into a more useful and modified form.
These synthesized products are usually more useful and made in order to solve a given problem or offer a particular service. Raw materials are cheaper than the synthesized products and are common in all industries and fields.
Mass of carbon = 0.1927 g
Mass of hydrogen = 0.02590 g
Mass of nitrogen = 0.1124 g
Mass of phosphorus = 0.1491 g
Mass of Oxygen = 0.8138 - ( 0.1927 + 0.02590 + 0.1124 + 0.1491 ) = 0.3337 g
Moles of C =
Moles of H = mol
Moles of O =
Moles of P =
Moles of N =
So, the empirical formula will be:
To make it a whole divide the moles of all elements by 0.00481.
Therefore, .
Molecular mass of ATP = 507 g/mol
Empirical formula = 164.063 g/mol
Molecular formula:
So, molecular formula is =
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Answer:
172.23L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 200 L
P1 (initial pressure) = 0.94 atm
T1 (initial temperature) = 25°C = 25 + 273 = 298K
P2 (final pressure) = 1atm
T2 (final temperature) = 0°C = 0 + 273 = 273K
V2 (final volume) =?
Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the container can be obtain as follow:
P1V1/T1 = P2V2/T2
0.94 x 200/298 = 1 x V2/273
Cross multiply to express in linear form as shown below:
298 x V2 = 0.94 x 200 x 273
Divide both side by 298
V2 = (0.94 x 200 x 273)/298
V2 = 172.23L
The new volume of the container is 172.23L