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3 years ago

Matter is never created or destroyed.

Chemistry

1 answer:

kumpel [21]3 years ago

8 0

I believe it is true!

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Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 24.0 atm. Calculate the work, w , if the gas exp

iVinArrow [24]

W = -P * delta V = - (1.00 atm)*(24.0 L - 1.00 L) = -23 L*atm (101.3 J/1 L*atm) = -233 J

4 0

3 years ago

What happens when cells are exposed to radioactivity?

Step2247 [10]

Answer:

when cell is exposed to radiation we get brain tumour or cancer.

6 0

3 years ago

Read 2 more answers

In the laboratory you dissolve 22.8 g of chromium(III) acetate in a volumetric flask and add water to a total volume of 250 mL.

IRINA_888 [86]

Answer:

The molarity of the chromium(III) acetate solution 0.3982 M.

0.3982 M is the concentration of the chromium(III) cation.

1.1946 M is the concentration of the acetate anion.

Explanation:

$Molarity=\frac{\text{Mass of substance}}{\text{Molar mass of substance}\times \text{Volume of solution(L)}}$

Mass of chromium(III) acetate = 22.8 g

Molar mass of chromium(III) acetate = 229 g/mol

Total volume of the solution of chromium(III) acetate = V = 250 mL = 0.250 L

1 mL = 0.001 L

The molarity of the chromium(III) acetate solution :

$[Cr(CH_3COO)_3]=\frac{22.8 g}{229 g/mol\times 0.250 L}=0.3982 M$

The molarity of the chromium(III) acetate solution 0.3982 M.

$Cr(CH_3COO)_3\rightarrow Cr^{3+}+3CH_3COO^-$

According to reaction, 1 mole of chromium(III) acetate gives 1 mole of chromium(III) ions and 3 moles of acetate ions.

So $[Cr^{3+}]=[Cr(CH_3COO)_3]=0.3982 M$

$[CH_3COO^-]=3\times [Cr(CH_3COO)_3]=3\times 0.3892 M=1.1946 M$

0.3982 M is the concentration of the chromium(III) cation.

1.1946 M is the concentration of the acetate anion.

5 0

3 years ago

A hard substance with a high melting point and poor conductor of electricity in the solid phase could be

VikaD [51]

MG its melting point is <span>1,202°F</span>

7 0

3 years ago

A radioactive isotope has a half-life of 3.0 hours. If a scientist has 30 grams of the isotope, how much is left after 15 hours?

dmitriy555 [2]

Answer:

0.9375

Explanation:

3.0x30x15 = 17 496 000 kg $sx^{2}$

subtract or divde

then you take the 9 and 375 add 0.9000 and combine them and there you go.

$+\frac{0.9000}{375} =0.9375$

7 0

3 years ago