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vlada-n [284]
3 years ago
8

How many atoms are present in 55 grams of iron

Chemistry
1 answer:
anastassius [24]3 years ago
4 0

Answer:

Atomic mass of iron is 55.9 amu.

Explanation:

So gram atomic mass of iron is 55.9 grams. Now we know the formula No. of moles = Given weight/ Molar Atomic weight. So, no. of moles = 65/55.9 No. of atoms = no. of moles x Avogadro number.

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A compound containing Na, C, and O is found to have 1.06 mol Na, 0.528 mol C, and 1.59 mol O. What is the empirical formula of t
Effectus [21]

Given :

Moles of Na : 1.06

Moles of C : 0.528

Moles of O : 1.59

To Find :

The empirical formula of the compound.

Solution :

Dividing moles of each atom with the smallest one i.e 0.528 .

So,

Na : 1.06/0.528 = 2.007 ≈ 2

C : 0.528/0.528 = 1

O : 1.59/0.528 = 3.011 ≈ 3

Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.

So, empirical formula is Na_2CO_3 .

Hence, this is the required solution.

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3 years ago
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LuckyWell [14K]
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8 0
4 years ago
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Korolek [52]
Your a furry cause I don’t know
3 0
3 years ago
What is the molarity of a solution that contains 0.400 mol HCI in 9.79 L solutions ​
USPshnik [31]

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In this case we are already given moles and liters so you just have to plug the numbers into the equation.

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If you were to use scientific notation, the answer will be: 4.1*10^-2, but otherwise, you can just use the decimals above and round appropriately as you see fit.

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Explanation:

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