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Arada [10]
3 years ago
14

Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 50 kg ball tra

veling at 10 m/s. A 50 kg ball traveling at 20 m/s would have kinetic energy. A 50 kg ball traveling at 5 m/s would have kinetic energy. A 50 kg person falling at 10 m/s would have kinetic energy.

Physics
2 answers:
Tasya [4]3 years ago
5 0

The formula for kinetic energy is  KE = (1/2) (mass) (speed²)

== The 50 kg ball traveling at 10 m/s has <em>some</em> kinetic energy.  

== A 50 kg ball traveling at 20 m/s would be moving at double the speed.  So it would have (2)² = <em>4 times as much</em> kinetic energy.

== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = <em>1/4 as much</em> kinetic energy.

== A 50 kg <u>person</u> falling at 10 m/s would have <em>exactly the same</em> amount of kinetic energy as the 50 kg <u>ball</u> traveling at 10 m/s.

Kisachek [45]3 years ago
3 0

A 50 kg ball traveling at 20 m/s would have <u>4 times more</u> kinetic energy.

A 50 kg ball traveling at 5 m/s would have <u>4 times less</u> kinetic energy.

A 50 kg person falling at 10 m/s would have <u>the same</u> kinetic energy.

Why?

Because:

<em>                                                #HappyCheating </em>

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This question involves the concepts of dynamic pressure, volume flow rate, and flow speed.

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Therefore,

v=\sqrt{\frac{2(379212\ Pa)}{1000\ kg/m^3}}

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Now, we will use the formula for volume flow rate of water coming from the hose to find out the time taken by the pool to be filled:

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where,

t = time to fill the pool = ?

A = Area of the mouth of hose = \frac{\pi (0.015875\ m)^2}{4} = 1.98 x 10⁻⁴ m²

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t = \frac{(100.1\ m^3)}{(1.98\ x\ 10^{-4}\ m^2)(27.54\ m/s)}\\\\

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Learn more about dynamic pressure here:

brainly.com/question/13155610?referrer=searchResults

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