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KIM [24]
2 years ago
9

What would spines be helpful for?

Physics
2 answers:
Komok [63]2 years ago
6 0
I would go with D is the best answer up here
ANEK [815]2 years ago
3 0
A and c...............................
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The electric field 30cm from a van de Graaff generator is measured to be 28,300N/C. What is the charge of the van de Graaf?
gizmo_the_mogwai [7]

Answer:

14

Explanation:

EWAN KO LANG DIN BASTA YAN ALAM KO

8 0
2 years ago
At what angle of projectile range of maximum​
Agata [3.3K]

Answer:

45°

Explanation:

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

7 0
3 years ago
Two rigid tanks of equal size and shape are filled with different gases. The tank on the left contains oxygen, and the tank on t
fredd [130]

Answer:

The number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.

Explanation:

Given:

Molar mass of oxygen, M_O=32

Molar mass of hydrogen, M_H=2

We know ideal gas law as:

PV=nRT

where:

P = pressure of the gas

V = volume of the gas

n= no. of moles of the gas molecules

R = universal gs constant

T = temperature of the gas

∵n=\frac{m}{M}

where:

m = mass of gas in grams

M = molecular mass of the gas

∴Eq. (1) can be written as:

PV=\frac{m}{M}.RT

P=\frac{m}{V}.\frac{RT}{M}

        as: \frac{m}{V}=\rho\ (\rm density)

So,

P=\rho.\frac{RT}{M}

Now, according to given we have T,P,R same for both the gases.

P_O=P_H

\rho_O.\frac{RT}{M_O}=\rho_H.\frac{RT}{M_H}

\Rightarrow \frac{\rho_O}{32}=\frac{\rho_H}{2}

\rho_O=16\rho_H

∴The molecules of oxygen are more densely packed than the molecules of hydrogen in the same volume at the same temperature and pressure. So, <em>the number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.</em>

5 0
2 years ago
Three resistors of 100 W, 3900 W, and 1000 W are connected in series across a 200-V battery. What is the voltage drop across the
Gala2k [10]

Answer:

40 V

Explanation:

 I will assume that  the resistors are

           100 and 3900 and 1000 OHMS    <=====(NOT W)

In series , the resistances add together 100 + 3900 + 1000 = 5000 ohms total

V = IR

I = V / R      so the total current will be   200 v / 5000 ohms = .04 amps

                   this is the current through all of the resistors

      so for the   1000 ohm resistor     V = IR     .04 (1000) = 40 V

7 0
2 years ago
Helppppppppp plzzzzzz
seropon [69]
I think number 1 is incorrect I believe that answer is D. Number 6 I believe would be B. The rest seem to be correct.
4 0
3 years ago
Read 2 more answers
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