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KIM [24]
3 years ago
9

What would spines be helpful for?

Physics
2 answers:
Komok [63]3 years ago
6 0
I would go with D is the best answer up here
ANEK [815]3 years ago
3 0
A and c...............................
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What is the theory of light?
Lostsunrise [7]

Answer:

Corpuscular theory of light

Explanation:

In optics, the corpuscular theory of light, arguably set forward by Descartes in 1637, states that light is made up of small discrete particles called "corpuscles" which travel in a straight line with a finite velocity and possess impetus. This was based on an alternate description of atomism of the time period.

3 0
3 years ago
2 Ten identical lengths of wire are laid closely side-by-
Mice21 [21]

Answer:

(a) 0.71 mm

(b) 0.158 cubic cm

Explanation:

The width of one wire is the diameter of the wire.

(a) Let the diameter of each wire is d.

So, 10 d = 14.2 mm

d = 1.42 mm

radius of each wire, r = d/2 = 1.42/2 = 0.71 mm

(b) Length, L = 10 cm

The volume of the single wire is given by

V =\pi\times r^2\times h \\\\V =3.14\times 0.071^2\times 10\\\\V =0.158 cm^3

7 0
2 years ago
Multidimensional development means that:
Snezhnost [94]

Answer:

option D

Explanation:

this is because it occurs in many different dimensions, including biological, cognitive and socioemotional. this is also the answer on apex.

5 0
3 years ago
A car is traveling down the highway at speed 5 m/s when the driver slams on the brakes and skids to a stop in a distance 80 m. A
Murljashka [212]
The car is very incredibly fast
8 0
3 years ago
The Moon's center is 3.9x10 m from Earth's center. The Moon is 1.5x10^8 km from the Sun's center. If the mass of the Moon is 7.3
nika2105 [10]

Explanation:

It is given that The Moon's center is 3.9x10⁸ m from Earth's center. The moon 1.5x10⁸ km from the Sun's center. We need to find the ratio of the gravitational forces exerted by Earth and the Sun on the Moon.

The gravitational force is given by :

F=\dfrac{Gm_em_m}{r^2}

It means F\propto \dfrac{1}{r^2}

So,

\dfrac{F_1}{F_2}=\dfrac{r_2}{r_1}

r₁ = 3.9x10⁸ km

r₂= 1.5x10⁸ km

So,

\dfrac{F_1}{F_2}=\dfrac{1.5\times 10^8}{3.9\times 10^8}\\\\\dfrac{F_1}{F_2}=\dfrac{5}{13}

Hence, the ratio of the gravitational forces exerted by Earth and the Sun on the Moon is 5:13.

3 0
3 years ago
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