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grandymaker [24]
2 years ago
6

In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good qu

estion about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good question about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good question about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good question about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good question about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good question about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good question about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.
Chemistry
1 answer:
Xelga [282]2 years ago
7 0

Answer:

Sample Response: How do mass and the type of material affect thermal energy transfer?

What did you include in your question? Check all that apply.

examines the effect of mass

examines the effect of different materials

contains at least two variables

Explanation:

<em> just did it on edge 2020</em>

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Under which of the following sets of conditions would the most o2 (g) be dissolved in h2o(l)?
jek_recluse [69]

Answer:

Oxygen will dissolve more in H2O at 5 atm and 20 °C than at 5 atm 80 °C

Option B is correct.

Explanation:

Step 1: Data given

Pressure = 5 atm

Temperature = 20 °C or 80 °C

Step 2:

At low pressure, a gas has a low solubility. Decreased pressure allows more gas molecules to be present in the air, with very little being dissolved in solution.  At high(er) pressure, a gas has a high solubility.

This means the higher the pressure the more the gas will dissolve. Since The pressure stays constant, it depends on the temperature.

The solubility of gases in liquids decreases with increasing temperature.

This means the gas will dissolve more with a lower temperature.

Oxygen will dissolve more in H2O at 5 atm and 20 °C than at 5 atm 80 °C

6 0
3 years ago
What does this “e” mean in science atoms molecules etc etc
Sedaia [141]

Answer:

electron in physics , and Element in chemistry.

5 0
3 years ago
Add 92.2 km to 9426 m and report the answer in
Mashcka [7]

to convert m into km we have to divide it by 1000.so,

9426/1000=9.426km

92.2km+9.426km=101.626km.

3 0
2 years ago
13.50 grams of Pb(NO3)4 are dissolved in enough water to make 250 mL of solution. What is the molar its of the resulting solutio
likoan [24]
Data:
M (molarity) = ? (M or Mol/L)
m (mass) = 13.50 g
V (volume) = 250 mL → 0.25 L
MM (Molar Mass) of Lead(IV) Nitrate Pb(NO_3)_4
Pb = 1*207 = 207 amu
N = (1*14)*4 = 14*4 = 56 amu
O = (3*16)*4 = 48*4 = 192 amu
------------------------------------
MM of Pb(NO_3)_4 = 207+56+192 = 455 g/mol

Formula:
M =  \frac{m}{MM*V}

Solving:
M = \frac{m}{MM*V}
M =  \frac{13.50}{455*0.25}
M =  \frac{13.50}{113.75}
M = 0.118681318...\:\:\to\:\:\boxed{\boxed{M \approx 0.119\:Mol/L}}\end{array}}\qquad\quad\checkmark

Answer:
<span>B. 0.119 M</span>
5 0
3 years ago
how much energy has your body used, in joules, if your health device indicates that 450 calories were burned during your workout
Likurg_2 [28]

Answer:

Total energy consumed = 1,882.8 joules

Explanation:

Given:

Calories burned = 450 calories

Find:

Total energy consumed

Computation:

1 calorie = 4.184 joules

So,

450 calories = 4.184 × 450

450 calories = 1,882.8 joules

Total energy consumed = 1,882.8 joules

7 0
3 years ago
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