8 gm of pure calcium is treated with 50 gram of pure Hcl to give cacl2 and h2 .which is limiting reactant?
1 answer:
Ca as a limiting reactant
<h3>Further explanation</h3>
Given
8 g Calcium
50 g HCl
<h3>Required</h3>
Limiting reactant
Solution
Reaction
Ca + 2HCl → CaCl₂ + H₂
mol Ca (Ar = 40 g/mol) :
= mass : Ar
= 8 g : 40 g/mol
= 0.2
mol HCl (MW= 36.5 g/mol) :
= mass : MW
= 50 g : 36.5 g/mol
= 1.37
Mol : coefficient reactants :
Ca = 0.2/1 = 0.2
HCl = 1.37/2 = 0.685
Ca as a limiting reactant(smaller ratio)
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