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Neporo4naja [7]
2 years ago
11

A force is applied to an object at rest with a mass of 100 kg. A force twice as large is applied to another object at rest with

a mass of 100 kg. What differences in their motion would you observe? Explain your reasoning.
Physics
1 answer:
MAVERICK [17]2 years ago
3 0
The second object, the one that had twice the force applied to it, would move twice as far, I believe.
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A beam of light strikes one face of a window pane with an angle of incidence of 30.0°. The index of refraction of the glass is 1
natka813 [3]

Answer:

(a). The angle of refraction is 19.26°.

(b). That is proved that the rays in air on either side of the glass are parallel to each other

Explanation:

Given that,

Angle of incidence = 30.0°

Index of reflection of glass = 1.52

(a). We need to calculate the angle of refraction for the ray inside the glass

Using snell's law

\dfrac{\sin i}{\sin r}=\mu

\sin r=\dfrac{\sin i}{\mu}

Put the value into the formula

\sin r=\dfrac{\sin 30}{1.52}

r=\sin^{-1}(0.329)

r=19.26^{\circ}

(b). We know that,

The incident ray and emerging ray  is equal then the ray will be parallel.

We need to prove that the rays in air on either side of the glass are parallel to each other

Using formula for emerging ray

\dfrac{\sin e}{\sin r}=\mu

\sin e=\sin r\times \mu

Put the value into the formula

\sin e=0.3289\times 1.52

e=\sin^{-1}(0.499)

e=29.9\approx 30^{\circ}

So, \sin i=\sin e

This is proved.

Hence, (a). The angle of refraction is 19.26°.

(b). That is proved that the rays in air on either side of the glass are parallel to each other

6 0
3 years ago
A container of soy milk has the instructions on its label to “shake well before opening ” The soy milk is most likely a ?
Elena-2011 [213]

Answer:

D. Suspension

4 0
3 years ago
In the Biomedical and Physical Sciences building at MSU there are 135 steps from the ground floor to the sixth floor. Each step
satela [25.4K]

Answer:

W = 16.5 Kj

P = 49.9 Watt

E = 16471

Explanation:

m = 73.5kg

t = 5min 30sec = (5×60) + 30 = 330sec

each step = 16.6cm = 0.166m

h = 135×0.166 = 22.41 m

g = 10 m/s²

(i) W = F × s = W × h = mgh

W = 73.5×10×22.41 = 16471.35

W = 16.5 Kj

(ii) Power = workdone/time

P = 16471.35/330

P = 49.9 Watt

(iii) The energy burnt in this process = 16471

4 0
3 years ago
Un cuerpo se mueve en línea recta segun la ecuación x=10+20t-4.9t2 (x está expresado en metros y t en segundos). ¿Cuál es la lon
lora16 [44]

Answer:

La longitud del camino recorrido es de 25.9 [m]

Explanation:

Se reemplaza el valor de tiempo en segundos en la ecuación dada de desplazamiento

x=10+20*(3) - 4.9*(3)^2

x= 25.9 [metros]

4 0
3 years ago
Read 2 more answers
a particle with a charge of 5.5 x 10^-8 c is 3.5 cm from a particle with a charge of -2.3 x10^-8 c. the potential energy of this
Yuri [45]

Answer:

-32.5 * 10^-5 J

Explanation:

The potential energy of this system of charges is;

Ue = kq1q2/r

Where;

k is the Coulumb's constant

q1 and q2 are the magnitudes of the charges

r is the distance of separation between the charges

Substituting values;

Ue = 9.0×10^9 N⋅m2/C2 * 5.5 x 10^-8 C *( -2.3 x10^-8) C/(3.5 * 10^-2)

Ue= -32.5 * 10^-5 J

4 0
3 years ago
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