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Svetllana [295]
3 years ago
9

Which of the following is not a constant or control for this experiment?

Physics
2 answers:
SCORPION-xisa [38]3 years ago
8 0
D.the amount of time in sun
Zepler [3.9K]3 years ago
8 0
Well, D. The amount of time in sun doesn't quite make sense yet the rest qualify as a constant or control. Yet, I suppose that under certain circumstances, D can also be considered a constant or control.
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Calculate the electric field strength at a point at which a test charge of 0.30 coulombs experiences a force of 5.0 newtons.
SVEN [57.7K]

The strength of electric field E is 17 N / C.

<u />

<u>Explanation:</u>

Electric field strength is defined as the force per unit charge acting at a point in the given field. The equation for the strength of the electric field is given by

                     E = F / q

where E represents the electric field strength,

           F represents the force in newton,

           q represents the charge in coulomb.

Given the charge q = 0.30 coulombs

                   force F = 5.0 N

Electric field strength E = force / charge

                                        = 5.0 / 0.30

                                    E  = 16.66 = 17 N / C.

5 0
3 years ago
When waves enter a denser medium, they bend the normal.<br><br> A) Toward<br> B) Away From
Andreyy89
The answer is bend towards normal.
7 0
3 years ago
Read 2 more answers
1. A Zambeef delivery track travels 18 km north, 10 km east, and 16 km south. What is its final displacement from the origin?
VARVARA [1.3K]

Answer:

2km

Explanation:

Given data

We are told that the direction traveled are

North>>>East>>>South

Hence the displacement is defined as the distance away from the initial position is

Initial position =18km

FInal position = 16km

The displacement = 18-16= 2km

Hence the displacement is 2km

6 0
3 years ago
(a) An object that has a small mass and an object that has a large mass have the same momentum. Which object has the largest kin
Iteru [2.4K]

Answer:

A) The smaller object; B) The larger object

Explanation:

A) Lets say the small object is 2 kg and the large one is 6 kg. Lets say they also have 30 kg*m/s of momentum each. The small object would have 15 m/s velocity and the large would have 5 m/s.

Now for kinetic energy(.5*m*v²), the small object is .5*2*15², which is 225 J

The large object is .5*6*5², which is 75 J, so the smaller object has more Kinetic energy. Since velocity is squared, it is more important than how large mass is.

B) Same masses as part A. Lets say the kinetic energy is 45 J for both of them. For the small object, 45=.5*2*v²

.5*2 is 1, so 45/1 is 45. Take the square root and we get v= 6.71 m/s

For the large object, 45=.5*6*v²

.5*6 is 3, so 45/3 is 15. Take the square root and we get v=3.87 m/s

Now we plug the velocities into p=mv

For the small object, p=2*6.71, which gives us p=13.42 kg*m/s

For the large object, p=6*3.87, which gives us p=23.22 kg*m/s

The larger object has the larger momentum.

Hope this helps

5 0
3 years ago
Find the net charge of a system consisting of 206 electrons and 161 protons. Express your answer using two significant figures.
kondaur [170]

Answer:

-72\times 10^{-19}C[/tex]

Explanation:

Both electron and proton have the same amount of charge but signs are opposite , electron contains negative charge and proton contain positive charge

Charge on 1 electron = -1.6\times 10^{-19}C

So charge on 206 electron =-206\times 1.6\times 10^{-19}C

Charge on 1 proton = -1.6\times 10^{-19}C

So charge on 161 electron =-106\times 1.6\times 10^{-19}C

So charge of the system = (-206+161)\times 1.6\times 10^{-19}C

=-72\times 10^{-19}C

5 0
3 years ago
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