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Kay [80]
2 years ago
10

A physical change occurs when a material changes shape or size but the composition of the material does not change. True or Fals

e?
Physics
1 answer:
Elden [556K]2 years ago
6 0
It is true that a physical change occurs when a material changes shape or size, but the composition of the material does not change. The correct answer is True. 
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What Is the volume of the rectangular prism of 6cm 9cm and 5cm
Crazy boy [7]
Volume is length  times width times height, so 6 times 9 times 5 is 270 centimeters.
8 0
3 years ago
If something changes motion, are forces balanced or unbalanced?
ololo11 [35]

When the motion of an object changes, the forces are unbalanced. Balanced forces are equal in size and opposite in direction. ... When the forces on an object are equal and in opposite directions, the forces are balanced, and there is no change in motion.

5 0
3 years ago
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What is the current in a circuit with a 4.5 V battery and a 9 Ω resistor?
horsena [70]

Answer:

V=I×R

<em>4</em><em>.</em><em>5</em><em> </em><em>=</em><em> </em><em>I×</em><em>9</em>

<em> </em><em> </em><em> </em><em>I</em><em>.</em><em> </em><em>=</em><em> </em><em>4</em><em>.</em><em>5</em><em>/</em><em>9</em>

<em> </em><em> </em><em> </em><em>I</em><em>. </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>

<em>curre</em><em>nt</em><em> </em><em>is</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>

3 0
2 years ago
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The wheels of a wagon can be approximated as the combination of a thin outer hoop, of radius ????h=0.209 m and mass 4.32 kg , an
Stolb23 [73]

Answer:

r= 98.3 mm

Explanation:

For rim

R= 0.209 m

M= 4.32 kg

For rods

m= 7.37 kg

L= 2 R= 2 x 0.209 = 0.418 m

The Total moment of inertia of the  wagon

I=MR²+2 x 1/12 m L²

Now by putting the values

I=4.32\times 0.209^2+2\times \dfrac{1}{12}\times 7.73\times 0.418^2\ kg.m^2

I=0.413 kg.m²

For disk:

t= 0.0462 m

Density ρ = 5990 kg/m³

Lets take r is the radius of disk

So the mass of the disc

m'=ρ πr² t

The moment of inertia of disc

I'=1/2 m'r²

I'=1/2 x r² x ρ πr² t

Given that

I = I'

1/2 x r² x ρ πr² t = 0.413 kg.m²

1/2 x r³ x ρ π t = 0.413

r³ x ρ π t = 0.826

r^3=\dfrac{0.826}{\pi \times 5990 \times 0.0462}

r³=0.00095

r=0.0983 m

r= 98.3 mm

8 0
3 years ago
What is the electrical force between q2 and q3? Recall that k = 8. 99 × 109 N•meters squared over Coulombs squared. 1. 0 × 1011
nlexa [21]

Force on the particle is defined as the application of the force field of one particle on another particle. the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

<h3>What is electric force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.

\rm F= K\frac{q_2q_3}{r^2}

\rm F= 9\times 10^9 \times \frac{1.6 \times 10^{-13}\times 1.6\times10^{-13}}{(0.5)^2}

\rm F=  - 1. 1 \times 10^{11 }N

Hence the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

To learn more about the electric force refer to the link;

brainly.com/question/1076352

4 0
2 years ago
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