2 years ago

I dont know what pfp to put on today so I'm asking u guys....

Physics

1 answer:

Mandarinka [93]2 years ago

5 0

Answer:

i think number 2 should be your pfp

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What is the elevation of Y and Z? Y=3250, Z=2950 Y=3200, Z=2900 Y=3250, Z=2900 Y=3000, Z=2850

TiliK225 [7]

I think the elevation of Y and Z are the following:
<span>Y=3200,
Z=2900 </span>

8 0

2 years ago

Which is a key criterion for the design of an automobile bumper?

Mrac [35]

Answer: The answer is A

Explanation: The bumper is the first part of an automobile to be impacted when in a head-on accident

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2 years ago

A bowling ball of 35.2 kg, generates 218 kg* m/s units of momentum. What is the velocity of the ball?

Aleonysh [2.5K]

Answer:

6.19 m/s

Explanation:

$p = mv \\ 218 = (35.2)(v ) \\ v = 6.19 \: ms {}^{ - 1}$

7 0

2 years ago

A helicopter starting on the ground is rising directly into the air at a rate of 25 ft/s. You are running on the ground starting

rusak2 [61]

Answer:

The rate of change of the distance between the helicopter and yourself (in ft/s) after 5 s is $\sqrt{725}$ ft/ sec

Explanation:

Given:

h(t) = 25 ft/sec

x(t) = 10 ft/ sec

h(5) = 25 ft/sec . 5 = 125 ft

x(5) = 10 ft/sec . 5 = 50 ft

Now we can calculate the distance between the person and the helicopter by using the Pythagorean theorem

$D(t) = \sqrt{h^2 + x^2}$

Lets find the derivative of distance with respect to time

$\frac{dD}{dt} (t) = \frac{2h \cdot \frac{dh}{dt} +2x \cdot\frac{dx}{dt}} {2\sqrt{h^2 + x^2}}$

Substituting the values of h(t) and x(t) and simplifying we get,

$\frac{dD}{dt}(t) = \frac{50t \cdot \frac{dh}{dt} + 20 \cdot \frac{dx}dt}{2\sqrt{625\cdot t^2 + 100 \cdot t^2}}$

$\frac{dh}{dt} = 25ft/sec$

$\frac{dx}{dt} = 10 ft/sec$

$\frac{Dd}{dt} (t) = \frac{1250t +200t}{2\sqrt{725}t}$ = $\frac{725}{\sqrt{725}}$ = $\sqrt{725}$ ft / sec

5 0

2 years ago

A car turns a certain curve of radius 24.98 m with constant linear speed of

Anastaziya [24]

Answer:

3525.19 kg

Explanation:

The computation of the mass of the car is shown below:

As we know that

Fc = m × V^2 ÷ R

m = Fc × R ÷ V^2

Provided that:

Fc = 34.652 kN = 34652 N

R = Radius = 24.98 m

V = speed = 15.67 m/s

So,

m = 34652 × 24.98 ÷ 15.67^2

= 3525.19 kg

7 0

2 years ago