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polet [3.4K]
2 years ago
9

What words go in the missing blanks?

Physics
1 answer:
docker41 [41]2 years ago
8 0
I would say mass, and weight.
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How much heat is required to heat 0.1 g of ∆hvap =2260 j/g ∆h =340j/g fus iceat−30ctosteamat100c? use the approximate values?
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How much heat<span> is </span>required<span> to </span>heat 0.1 g<span> of </span>∆hvap<span> =</span>2260 j/g ∆h<span> =</span>340j/g fus iceat−30 ctosteamat 100c?use<span> the </span>approximate values<span>?</span>
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3 years ago
Ball B is suspended from a cord of length l attached to cart A, which can roll freely on a frictionless, horizontal track. The b
Kazeer [188]

Answer:

a.Velocity of A and Velocity of B will be opposite in direction.

b.Both velocities have the same direction.

c. The two objects will move in a direction of some angle α.  

Explanation:

When the angle gets maximum the velocities of the two objects pull each other and move in opposite direction. But when the two objects make an angle zero degree with each other their motion is in the same direction.  

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3 years ago
Select all of the answers that apply. The greenhouse effect is very important to daily life on earth. Which of the following are
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Carbon dioxide, nitrous oxide, methane and ozone are all greenhouse gases.
5 0
3 years ago
Read 2 more answers
A marching band consists of rows of musicians walking in straight, even lines. When a marching band performs in an event, such a
Svetllana [295]

Answer:

a. 4v

Explanation:

Alf moves with speed v

Alf travel during the same amount of time that is Δt = (1/4)s

v = (1/4)s /  Δt = s / 4 Δt

s / Δt  = 4 v

Beth travels a distance s during time Δt,

speed of Beth = s / Δt = 4 v .

7 0
3 years ago
The electric motor of a model train accelerates the train from rest to 0.685 m/s in 21.5 ms. The total mass of the train is 875
Natali [406]

Answer:

P=9.58 W

Explanation:

According to Newton's second law, and assuming friction force as zero:

F_m=m.a\\F_m=0.875kg*a

The acceleration is given by:

a=\frac{\Delta v}{t}\\a=\frac{0.685m/s}{21.5*10^{-3}s}\\\\a=31.9m/s^2

So the force exerted  by the motor is:

F_m=0.875kg*31.9m/s^2\\F_m=27.9N

The work done by the motor is given by:

W_m=F_m*d\\\\d=\frac{1}{2}*a*t^2\\d=\frac{1}{2}*31.9m/s^2*(21.5*10^{-3}s)^2\\\\d=7.37*10^{-3}m

W_m=27.9N*7.37*10^{-3}m\\W_m=0.206J

And finally, the power is given by:

P=\frac{W_m}{t}\\P=\frac{0.206J}{21.5*10^{-3}s}\\\\P=9.58W

8 0
3 years ago
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