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AlekseyPX
2 years ago
5

After studying chemical reactions in school, Jen examined some of the different ways people use synthetic materials. She found t

hat there are a variety of ways people use them. What are some of the ways people use these materials and why?
Please help out
Chemistry
2 answers:
Veseljchak [2.6K]2 years ago
8 0
When using a dryer to dry your clothes your clothes become synthetic after drying clothes
dlinn [17]2 years ago
5 0
What he said lskfbekkfnsjkfkdjjfjfjkdjf
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Please show the work :(What is the estimated force applied to the box if the acceleration is .40 m/s2?
lara31 [8.8K]

Answer:

20N

Explanation:

Given parameters:

        Force(N)     Acceleration(m/s²)  

            10                   0.2

           ?                      0.4

Unknown:

The force applied when the acceleration is 0.4m/s²

Solution:

From newton's second law of motion;

 Force = mass x acceleration

 Since we are using the same box, let us find the mass of the box;

      Force  = mass x acceleration

         10 = mass x 0.2

            mass = \frac{10}{0.2}  = 50kg

Now,

 The force in the second instance will be;

      Force  = 50 x 0.4  = 20N

8 0
2 years ago
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stira [4]

Answer:

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7 0
2 years ago
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When performing labratory experiments, which of the following items is ALWAYS necessary to use?
densk [106]
All of the the answers are are correct but a fume hood is more for if you are dealing with chemicals that can produce fumes the are deadly to people
3 0
3 years ago
Which factor below does not affect how fast a solute dissolves in a solvent?
Anit [1.1K]
Stirring this is because the three elements are factors affecting dissolving of a solvent. Eg temprature affects in hotness or coldness, Particle size affects whether it is big or small while quantity of soluble affects by the amount
3 0
3 years ago
Read 2 more answers
Suppose a 250. mL flask is filled with 0.30 mol of N_2 and 0.70 mol of NO. The following reaction becomes possible:N_2(g) +O2 →
Inessa [10]

Answer:

0.4 M

Explanation:

Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.

Because there's no O₂ in the beginning, the NO will decompose:

N₂(g) + O₂(g) ⇄ 2NO(g)

0.30 0 0.70 Initial

+x +x -2x Reacts (the stoichiometry is 1:1:2)

0.30+x x 0.70-2x Equilibrium

The equilibrium concentrations are the number of moles divided by the volume (0.250 L):

[N₂] = (0.30 + x)/0.250

[O₂] = x/0.25

[NO] = (0.70 - 2x)/0.250

K = [NO]²/([N₂]*[O₂])

K = \frac{(\frac{0.70 -2x}{0.250})^2 }{\frac{0.30+x}{0.250}*\frac{x}{0.250} }

7.70 = (0.70-2x)²/[(0.30+x)*x]

7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)

4x² - 2.80x + 0.49 = 2.31x + 7.70x²

3.7x² + 5.11x - 0.49 = 0

Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70

x = 0.09 mol

Thus,

[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M

3 0
3 years ago
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