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3 years ago

What is the name of the system for conducting a scientific investigation?

Physics

1 answer:

Slav-nsk [51]3 years ago

5 0

Answer:

i beleive it is 2

Explanation:

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A marble is dropped off the top of a building. Find it's velocity and how far below to its dropping point for the first 10 secon

Yuri [45]

consider the motion in y-direction

v₀ = initial velocity = 0 m/s

a = acceleration = g = - 9.8 m/s²

t = time

v = final velocity at any time "t"

velocity at any time is given as

v = v₀ + at

v = 0 + (- 9.8) t

v = (- 9.8) t

so at t = 1 , v = (- 9.8) (1) = - 9.8 m/s

at t = 2 , v = (- 9.8) (2) = - 19.6 m/s

at t = 3 , v = (- 9.8) (3) = - 29.4 m/s and so on

Y₀ = initial position where the marble was dropped from = 0 m

Y = final position at any time "t"

final position at any time "t" is given as

Y = Y₀ + v₀ t + (0.5) a t²

Y = 0 + (0) t + (0.5) (-9.8) t²

Y = - 4.9 t²

at t = 1 , Y = - 4.9 (1)² = - 4.9 m

at t = 2 , Y = - 4.9 (2)² = - 19.6 m

at t = 3 , Y = - 4.9 (3)² = - 44.1 m

and So on

6 0

3 years ago

What can we say about a polarizing filter with vertically aligned chemical molecules?

klemol [59]

Answer:

A . It will allow vertically polarized light to pass through it.

Explanation:

Polarization is the attribute in which waves oscillate in a particular direction relative to the direction of travel. The direction of polarization determines the type of polarized light produced. Since the chemical molecules are vertically aligned, it will only allow vertically polarized light pass through it.

3 0

4 years ago

I need help pls help

Nikitich [7]

You want all those boxes filled in (0,0)

5 0

4 years ago

A rocket achieves lift off due to ______.

Alex17521 [72]

B.) Action and reaction forces helps during lift off of a rocket.

Hope this helps!

4 0

4 years ago

Read 2 more answers

A point charge Q is located a short distance from a point charge 3Q, and no other charges are present. If the electrical force o

weeeeeb [17]

Answer:

d) F

Explanation:

According to columb's law:

"The magnitude of electrostatic force between two charges is directly proportional to the product of magnitude of two charges and inversly proportional to separation between them."

If q₁ and q₂ are magnitude of two charges, d is distance between them and k is dielectric constant, then force F is given by

$F=\frac{kq_{1}q_{2}}{d^2}$

According to this force exerted on point charge Q is same as that of 3Q, so force point 3Q charge experience is also F

7 0

3 years ago