Using the number line below, draw a box and whisker plot for the following data: 12,18,18,20,22,22,25,26,30,30,32,32,35,35,38,49
Dmitry_Shevchenko [17]
Answer:
Step-by-step explanation:
Population size: 17
Median: 30
Minimum: 12
Maximum: 49
First quartile: 21
Third quartile: 35
Interquartile Range: 14
Outliers: none
Find out what the variable.
Answer:Quadratic
Step-by-step explanation:
As the domain values negative infinity, the range values approach infinity.
Domain: If then X=- Infinity
Range:Y= infinity
We need to settle on correct option which follows given domain and range.
Only quadratic function will follow the rule because it's even degree polynomial.
Quadratic function:f(X)= aX^2+bX+c
Degree = 2 and leading coefficient is positive.
Domain:X(-infinity, infinity)
Range: Y(b, Infinity)
Think of x(symbol)y as a function like f(x)=3x-y. Since the first symbol we see is in parenthesis, we know that x=-1 and y=-2. Plug that into f(x), and you get 3(-1)-(-2)=-1. So know we have the x value for the second symbol, which is -1, and the y value, which is seen to the right: (-3). Plug that back into f(x), and you get 3(-1)-(-3)= 0. Your answer should be A: 0.
Alright, so the population of the herd is 220 in 2012. This means that when it decreased by 10 percent in 2014, 10 percent of the population is taken away. To find 10 percent of the population, we simply multiply 220 by 0.1 due to that to get a percentage as a decimal, we simply divide the percentage amount by 100. In addition, as the elk population in 2012 represents 100% of the elk population that we’re starting with (100%=1, or the whole thing), 10% subtracted from 100% is 90% of the population, or 220*0.9 as the population in 2013. To get the population in 2014, we have to multiply the population in 2013 by 0.9 similar to how we got from 2012 to 2013. This means we multiply (220*0.9)*0.9=178.2, which rounds down to 178 as the next number, 2, is less than 5. If that 2 were to be 5 or higher, we would round up to 179.
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