Answer:
1.553 M^2s^-1
Explanation:
Now let us consider experiments 1,2,3.
In experiment 1 and 2, the concentration of NO is doubled and the initial rate of reaction is quadrupled.
0.575/0.144 = 4
So;
2^2 =4
In experiment 2 and 3
The concentration of reaction of H2 is doubled and the rate of reaction is doubled.
0.575/0.287 = 2
2^1 =2
So we can now write;
Rate =k[NO]^2 [H2]^1
Taking up the first reaction;
0.144 =k [0.475]^2 [0.411]
k = 0.144/ [0.475]^2 [0.411]
k = 1.553 M^2s^-1
