Question

Review Toples

Answer 1

Answer:

1.553 M^2s^-1

Explanation:

Now let us consider experiments 1,2,3.

In experiment 1 and 2, the concentration of NO is doubled and the initial rate of reaction is quadrupled.

0.575/0.144 = 4

So;

2^2 =4

In experiment 2 and 3

The concentration of reaction of H2 is doubled and the rate of reaction is doubled.

0.575/0.287 = 2

2^1 =2

So we can now write;

Rate =k[NO]^2 [H2]^1

Taking up the first reaction;

0.144 =k [0.475]^2 [0.411]

k = 0.144/ [0.475]^2 [0.411]

k = 1.553 M^2s^-1