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3 years ago

Find an equation of the line perpendicular to the graph.

Mathematics

1 answer:

topjm [15]3 years ago

8 0

Answer:

The equation of the line would be y = -1/4x + 2

Step-by-step explanation:

In order to solve this, start by finding the slope of the original line. You can do this by solving for y.

28x - 7y = 9

-7y = -28x + 9

y = 4x - 9/7

Now that we have a slope of 4, we know that the perpendicular slope is -1/4 (since perpendicular lines have opposite and reciprocal slopes). We can use this and the new point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 1 = -1/4(x - 4)

y - 1 = 1/4x + 1

y = -1/4x + 2

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telo118 [61]

Answer:

$\huge\boxed{\sf A = 78.5\ ft\²}$

Step-by-step explanation:

Circumference = C = 31.4 ft

We know that,

Where, r is the radius

31.4 = 2(3.14)r

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Divide 6.28 to both sides

31.4/6.28 = r

5 ft. = r

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Step-by-step explanation:

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4(a x b)=(4 x a)b is an example of which algebraic property

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3 years ago

find a function whose second derivative is y''=12x-2 at each point (x,y) on its graph and y=-x+5 is tangent to the graph at the

pogonyaev

Start by integrating y'' twice to get function y(x).

$y' = \int (12x - 2) dx = 6x^2 -2x + c \\ \\ y = \int (6x^2 -2x+c )dx= 2x^3-x^2 +cx+d$

Next find value of coefficients 'c' and 'd' using the given tangent line
The slope of tangent line is equal to y' when x=1.

$6x^2 -2x+c = -1, x = 1 \\ \\ 6-2+c = -1 \\ \\ c = -5$

The tangent line intersects the curve y(x) when x = 1.
If x = 1, then y = 4 (From y =-x+5)

$y = 2x^3 -x^2-5x +d , x = 1, y = 4 \\ \\ 2-1-5+d = 4 \\ \\ d = 8$

Final Answer:
$y = 2x^3 -x^2 -5x+8$

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