All categories

3 years ago

What does it mean by km/h/s?

Physics

2 answers:

Leona [35]3 years ago

7 0

km means kilometers which is the measuring system for distance, /h/s means per hour.

Example: i was going 160 km/h/s

Meaning: i was going 160 kilometers per hour.

Hope i helped!

Salsk061 [2.6K]3 years ago

5 0

Km/h/s means Kilometers per hour per second.

You might be interested in

The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by variou

zlopas [31]

Answer:

q = 3.6 10⁵ C

Explanation:

To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth

r = 6 , 37 106 m

E = k q / r²

q = E r² / k

q = $\frac{100 \ (6.37 \ 10^6)^2}{9 \ 10^9}$

q = 4.5 10⁵ C

Now let's calculate the charge on the planet with E = 222 N / c and radius

r = 0.6 r_ Earth

r = 0.6 6.37 10⁶ = 3.822 10⁶ m

E = k q / r²

q = E r² / k

q = $\frac{222 (3.822 \ 10^6)^2}{ 9 \ 10^9}$

q = 3.6 10⁵ C

4 0

3 years ago

If a = 2.0 cm, b = 5.0 cm, and i = 20 a, what is the magnitude of the magnetic field at the point p?

attashe74 [19]

If a = 2.0 cm, b = 5.0 cm, and i = 20 a, 6.0 μt is the magnitude of the magnetic field at the point p, So the correct option is (a).

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

$B_{1}$ = μ $_{0}$ i $\frac{\pi }{6}$ / $4\pi (a+b)$

$B_{2}$ = μ $_{0}$ i $\frac{\pi }{6}$ / $4\pi b$

As, $B_{1}$ is moving down and $B_{2}$ is moving up so,

$B_{2}$ - $B_{1}$ = (μ $_{0}$ i $\frac{\pi }{6}$ / $4\pi b$ ) - [μ $_{0}$ i $\frac{\pi }{6}$ / $4\pi (a+b)$ ]

$B_{2}$ - $B_{1}$ = μ $_{0}$ i 24 / $(\frac{1}{b} - \frac{1}{a+b} )$

$B_{2}$ - $B_{1}$ = $\frac{4\pi *10^{-7}*20 }{24} (\frac{1}{0.05} -\frac{1}{0.02})$

$B_{2}$ - $B_{1}$ = 5.98× $10^{-6}$ T ≈ 6μT

Therefore, 6.0 μt is the magnitude of the magnetic field .

Learn more about magnetic field here;

brainly.com/question/23096032

#SPJ4

3 0

2 years ago

The severity of a fall depends on your speed when you strike the ground. All factors but the acceleration from gravity being the

Diano4ka-milaya [45]

Answer:

<em>The object could fall from six times the original height and still be safe</em>

Explanation:

<u>Free Falling</u>

When an object is released from rest in free air (no friction), the motion is completely dependant on the acceleration of gravity g.

If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy of

$U=m.g.h$

When the object strikes the ground, all the mechanical energy (only potential energy) becomes into kinetic energy

$\displaystyle K=\frac{1}{2}m.v^2$

Where v is the speed just before hitting the ground

If we know the speed v is safe for the integrity of the object, then we can know the height it was dropped from

$\displaystyle m.g.h=\frac{1}{2}m.v^2$

Solving for h

$\displaystyle h=\frac{m.v^2}{2mg}=\frac{v^2}{2g}$

If the drop had occurred in the Moon, then

$\displaystyle h_M=\frac{v_M^2}{2g_M}$

Where hM, vM and gM are the corresponding parameters on the Moon. We know v is the safe hitting speed and the gravitational acceleration on the Moon is g_M=1/6 g

$\displaystyle h_M=\frac{v^2}{2\frac{1}{6}g}$