Displaced volume:
final volume - initial volume
1 mL = 1 cm³
38.5 mL - 35.0 mL = 3.5 cm³
hope this helps!
Answer:
[HAc] = 0.05M
[Ac⁻] = 0.20M
Explanation:
The Henderson-Hasselbalch formula for the acetic acid buffer is:
pH = pka + log₁₀ [Ac⁻] / [HAc]
Replacing:
5.36 = 4.76 + log₁₀ [Ac⁻] / [HAc]
3.981 = [Ac⁻] / [HAc] <em>(1)</em>
Also, as total concentration of buffer is 0.25M it is possible to write:
0.25M = [Ac⁻] + [HAc] <em>(2)</em>
Replacing (2) in (1)
3.981 = 0.25M - [HAc] / [HAc]
3.981 [HAc] = 0.25M - [HAc]
4.981 [HAc] = 0.25M
<em>[HAc] = 0.05M</em>
Replacing this value in (2):
0.25M = [Ac⁻] + 0.05M
<em>[Ac⁻] = 0.20M</em>
I hope it helps!
Answer:
The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³
Explanation:
Step 1: Data given
For the reaction aA + bB ⇆ cC + dD
the equilibrium constant Kc = [C]^c * [D]^d/[B]^b*[A]^a
Step 2: The balanced equation
Fe2O3(s) + 3H2(g) --> 2Fe(s) + 3H2O(g)
Step 3: Calculate the equilibrium constant Kc
Kc = [C]^c * [D]^d/[B]^b*[A]^a
⇒with [C] = [Fe]
⇒ with c = 2
⇒with [D] = [H2O]
⇒with d = 3
⇒with [A] = [Fe2O3]
⇒with a = 1
⇒with [B] = [H2]
⇒with b = 3
Kc = [C]^c * [D]^d/[B]^b*[A]^a
Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³
The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³
x + y = 100
0.10x + 0.45 y =25
eliminate
x + y = 100
x + 4.5 y = 250
-3.5 y = -150
y = 42.85
x = 57.15
hope this helps
<span>Explain the difference between a weak acid and a strong acid according to the Arrhenius theory his question in english</span>
