I believe C is the answer <span />
An osmolarity of saline solution is 308 mosmol/L.
m(NaCl) = 9 g; the mass of sodium chloride
V(solution) = 1 L; the volume of the saline solution
n(NaCl) = 9 g ÷ 58.44 g/mol
n(NaCl) = 0.155 mol; the amount of sodium chloride
number of ions = 2
Osmotic concentration (osmolarity) is a measure of how many osmoles of particles of solute it contains per liter.
The osmolarity = n(NaCl) ÷ V(solution) × 2
The osmolarity = 0.154 mol ÷ 1 L × 2
The osmolarity = 0.154 mol/L × 1000 mmol/m × 2
The osmolarity of the saline solution = 308 mosm/L.
More about osmolarity: brainly.com/question/13258879
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Convert gal to liters:
14.0 gal x 3.785 L / gal = 53.0 L
Multiply volume by density (the density would have the units of .758 g/mL or .758 kg / L)
53.0 L x .758 kg/L = <span> 40.2 kg</span>
Answer:
The substance is most likely NaCl.
Explanation:
Solubility:
As stated in statement the substance is insoluble in CCl₄ (Tetrachloromethane), it shows that the substance is polar in nature. In given options only C₁₀H₈ is soluble in CCl₄ because both are non polar in nature and like dissolves like. Hence, C₁₀H₈ is rejected.
Density:
Now, we are left with three options. NaCl, FeCl₃ and SiO₂. The student found that the density of substance is 2.20 g.mL⁻¹. Which is very close to the density of NaCl (i.e. 2.165 g.mL⁻¹). Therefore, most probably the substance the student is dealing with is Sodium Chloride.
