Based on this scatter plot, I can say that in general, test scores vary directly with study time. In other words, in a population large enough to reveal the direct relationship, the more time a student spends studying, the higher that student's test scores will be.
I didn't need a scatter plot to reveal that to me. That's practically in the category of Law given to Moses at Sinai.
Answer:
The buoyant force experienced by a body is equal to product of unit weight of liguid in which the the objevt is immersed and the volume of liquid replaced by the object.
In the given scenario, bothe the spheres have equal volume and are fully submerged in water. Therefore, the buoyant force experienced by both the spheres will be equal.
Answer:
The velocity of the man is 0.144 m/s
Explanation:
This is a case of conservation of momentum.
The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.
Mass of ball = 0.65 kg
Mass of the man = 54 kg
Velocity of the ball = 12.1 m/s
Before collision, momentum of the ball = mass x velocity
= 0.65 x 12.1 = 7.865 kg-m/s
After collision the momentum of the man and ball system is
(0.65 + 54)Vf = 54.65Vf
Where Vf is their final common velocity.
Equating the initial and final momentum,
7.865 = 54.65Vf
Vf = 7.865/54.65 = 0.144 m/s
Answer:
it should be tension for the space
Answer: 70m
Explanation:
Given, 2 skaters, one with a mass of 60kg.
Another 75kg.
Distance is 14m.
Assuming the system centre if mass does not change, both skaters would meet at the centre of the mass
let the 60kg skater be xm away from the centre, then, the 75kg skater would be (14 - x)m away from the centre too
m1x + m2(14 - x) = 0
m1x + 14m2 - m2x = 0
60x + 14*75 - 75x = 0
60x - 75x + 1050 = 0
-15x + 1050 = 0
15x = 1050
x = 70
Thus, the distance the 65kg skater moves is 70m