1.41 × 10³⁰ MeV
As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).
Given mass = 2.5 kgs
∴ E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J
As our answer is in joules so we have to convert it into mega electron volt(MeV)
1 J = 6.242 × 10¹² MeV
⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV
⇒1.41 × 10³⁰ MeV
If you want to learn more about mass-energy conversions then you can check out this link:
https://brainly.in/question/9760064
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Rabbits
Mates
In
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Unusual
e(X)pensive
Gardens
Explanation:
The given data is as follows.
Temperature of metal =
= (296 + 273) K
= 569 K
Density of the metal = 8.85
=
(as
)
Atomic mass = 51.40 g/mol
Vacancies = 
Formula to calculate the number of atomic sites is as follows.
n = 
= 
= 
Now, we will calculate the energy as follows.
E = 
where, K = 
E = 
= 
Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is
.
Answer:
Explanation:
maximum energy of capacitor
E = 1/2 C V ²
C is capacitance of capacitor and V is potential difference
given V = 88 V
E = 2002 x 10⁻⁶ J
Putting the values
2002 x 10⁻⁶ = 1/2 x C x 88²
C = .517 x 10⁻⁶ F .
In the second case
Energy E = 125 x 10⁻⁶ J .
C = .517 x 10⁻⁶
V = ?
E = 1/2 C V ²
125 x 10⁻⁶ = 1/2 x .517 x 10⁻⁶ x V²
V² = 483.55
V = 21.98 V .